Jump to content

Arithmetic IF

From Wikipedia, the free encyclopedia
(Redirected from Arithmetic if)

The arithmetic IF statement is a three-way arithmetic conditional statement, first seen in the first release of Fortran in 1957, and found in all later versions[a], and some other programming languages, such as FOCAL. Unlike the logical IF statements seen in other languages, the Fortran statement defines three different branches depending on whether the result of an expression is negative, zero, or positive, in said order, written as:

     IF (expression) negative,zero,positive

Deprecation[edit]

While it originally was the only kind of IF statement provided in Fortran, the feature has been used less and less frequently after the logical IF statements were introduced, and was finally labeled obsolescent in Fortran 90. As of Fortran 2018, it is no longer required for compilers to implement arithmetic IF and it is considered to be a deleted feature. The GNU Fortran compiler has been producing warnings for arithmetic IF by default since its 9.1 release in 2019.[citation needed]

See also[edit]

Notes[edit]

  1. ^ Might not be present in a Fortran 2018 compiler. See the Deprecation section.

References[edit]