1959 Wimbledon Championships

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1959 Wimbledon Championships
Date:   22 June – 3 July
Edition:   73rd
Category:   Grand Slam
Surface:   Grass
Location:   Church Road
SW19, Wimbledon
London, United Kingdom
Champions
Men's Singles
United States Alex Olmedo[1]
Women's Singles
Brazil Maria Bueno[2]
Men's Doubles
Australia Roy Emerson / Australia Neale Fraser[3]
Women's Doubles
United States Jeanne Arth / United States Darlene Hard[4]
Mixed Doubles
United States Darlene Hard / Australia Rod Laver[5]
Boys' Singles
Soviet Union Toomas Lejus[6]
Girls' Singles
South Africa Joan Cross[7]
Wimbledon Championships
 < 1958 1960 > 

The 1959 Wimbledon Championships took place on the outdoor grass courts at the All England Lawn Tennis and Croquet Club in Wimbledon, London, United Kingdom. The tournament ran from 22 June until 3 July. It was the 73rd staging of the Wimbledon Championships, and the third Grand Slam tennis event of 1959.

Champions[edit]

Men's Singles[edit]

United States Alex Olmedo defeated Australia Rod Laver, 6–4, 6–3, 6–4.[1]

Women's Singles[edit]

Brazil Maria Bueno defeated United States Darlene Hard, 6–4, 6–3.[2]

Men's Doubles[edit]

Australia Roy Emerson / Australia Neale Fraser defeated Australia Rod Laver / Australia Bob Mark, 8–6, 6–3, 14–16, 9–7.[3]

Women's Doubles[edit]

United States Jeanne Arth / United States Darlene Hard defeated United States Beverly Baker Fleitz / United Kingdom Christine Truman, 2–6, 6–2, 6–3.[4]

Mixed Doubles[edit]

United States Darlene Hard / Australia Rod Laver defeated Brazil Maria Bueno / Australia Neale Fraser, 6–4, 6–3.[5]

Boys' Singles[edit]

Soviet Union Toomas Lejus[6]

Girls' Singles[edit]

South Africa Joan Cross[7]

References[edit]

External links[edit]


Preceded by
1959 French Championships
Grand Slams Succeeded by
1959 U.S. National Championships