2019 Tata Open Maharashtra – Doubles

From Wikipedia, the free encyclopedia

Doubles
2019 Tata Open Maharashtra
Final
ChampionsIndia Rohan Bopanna
India Divij Sharan
Runners-upUnited Kingdom Luke Bambridge
United Kingdom Jonny O'Mara
Score6–3, 6–4
Details
Draw16
Seeds4
Events
Singles Doubles
← 2018 · Maharashtra Open · 2020 →

Robin Haase and Matwé Middelkoop were the defending champions, but chose to compete in Doha instead.

Rohan Bopanna and Divij Sharan won the title, defeating Luke Bambridge and Jonny O'Mara in the final, 6–3, 6–4.

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First round Quarterfinals Semifinals Final
1 India R Bopanna
India D Sharan
6 6
  Moldova R Albot
Tunisia M Jaziri
1 2 1 India R Bopanna
India D Sharan
64 6 [17]
  India L Paes
Mexico MÁ Reyes-Varela
6 6 India L Paes
Mexico MÁ Reyes-Varela
77 4 [15]
  Spain D Marrero
Chile H Podlipnik Castillo
3 4 1 India R Bopanna
India D Sharan
6 3 [15]
3 El Salvador M Arévalo
United States J Cerretani
6 5 [7] Italy S Bolelli
Croatia I Dodig
3 6 [13]
  Italy S Bolelli
Croatia I Dodig
4 7 [10] Italy S Bolelli
Croatia I Dodig
6 6
  Germany K Krawietz
Germany A Mies
7 6 Germany K Krawietz
Germany A Mies
2 4
  Poland H Hurkacz
France B Paire
5 3 1 India R Bopanna
India D Sharan
6 6
  Ukraine D Molchanov
Slovakia I Zelenay
6 6 United Kingdom L Bambridge
United Kingdom J O'Mara
3 4
  Spain P Andújar
Spain R Carballés Baena
1 4 Ukraine D Molchanov
Slovakia I Zelenay
4 77 [6]
  United States N Monroe
India J Nedunchezhiyan
4 4 4 Spain G Granollers
Spain M Granollers
6 63 [10]
4 Spain G Granollers
Spain M Granollers
6 6 4 Spain G Granollers
Spain M Granollers
4 6 [6]
  United Kingdom L Bambridge
United Kingdom J O'Mara
77 6 United Kingdom L Bambridge
United Kingdom J O'Mara
6 3 [10]
WC India P Raja
India R Ramanathan
64 3 United Kingdom L Bambridge
United Kingdom J O'Mara
77 6
WC India S Balaji
India A Kadhe
77 4 [10] WC India S Balaji
India A Kadhe
65 1
2 Austria P Oswald
Germany T Pütz
61 6 [8]

External links[edit]