Aaron Island (Alaska)
 | |
| Geography | |
|---|---|
| Location | Juneau City and Borough, Alaska |
| Coordinates | 58°26′16″N 134°49′10″W / 58.43778°N 134.81944°W |
| Archipelago | Alexander Archipelago |
| Length | 0.4 mi (0.6 km) |
| Highest elevation | 0 ft (0 m) |
| Administration | |
United States | |
| State | Alaska |
| Borough | Juneau |
Aaron Island is an island in the City and Borough of Juneau, Alaska, United States. It was named by Lester A. Beardslee in 1880.[1] Located in Lynn Canal, it is 1.2 miles (1.9 km) northwest of Point Stephens and 17 miles (27 km) northwest of the city of Juneau.[2]
The island was formerly listed as 174 feet (53 m) high.[3]
References[edit]
- ^ Baker, Marcus. Geographic Dictionary of Alaska, Second Edition. p. 79. Washington: Government Printing Office, 1906.
- ^ USGS GNIS Feature Detail Report: Aaron Island
- ^ U.S. Coast and Geodetic Survey. United States Coast Pilot: Alaska, Part I: Dixon Entrance to Yakutat Bay, Sixth Edition, p. 160. Washington: Government Printing Office, 1917.
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