Alternating series test

From Wikipedia, the free encyclopedia

Jump to: navigation, search

The alternating series test is a method used to prove that infinite series of terms converge. It was discovered by Gottfried Leibniz and is sometimes known as Leibniz's test or the Leibniz criterion.

A series of the form

 \sum_{n=0}^\infty (-1)^n a_n\!

where all the an are non-negative, is called an alternating series. If the limit of the sequence an equals 0 as n approaches infinity, and each an is smaller than an-1 (i.e. the sequence an is monotone decreasing), then the series converges. If L is the sum of the series,

\sum_{n=0}^\infty (-1)^n a_n = L\!

then the partial sum

S_k = \sum_{n=0}^k (-1)^n a_n\!

approximates L with error

\left | S_k - L \right \vert \le \left | S_k - S_{k-1} \right \vert = a_k\!

It is perfectly possible for a series to have its partial sums Sk fulfill this last condition without the series being alternating. For a straightforward example, consider:

\sum_{n=0}^\infty \left(\frac{1}{3}\right)^n  = \frac{3}{2}\!

Contents

[edit] Proof

[1]

We are given a series of the form \sum_{n=0}^\infty (-1)^n a_n\!. The limit of the sequence an equals 0 as n approaches infinity, and each an is smaller than an − 1 (i.e. the sequence an is monotone decreasing).

[edit] Proof of convergence

The (2n+1)-th partial sum of the given series is S_{2n+1}  = a_0  + \left( { - a_1  + a_2 } \right) + \left( { - a_3  + a_4 } \right) + \ldots + \left( { - a_{2n - 1}  + a_{2n} } \right) - a_{2n+1} . As every sum in brackets is non-positive, and as a_{2n+1}  \geq 0, then the (2n+1)-th partial sum is not greater than a0.

That very (2n+1)-th partial sum can be writen as S_{2n+1}  = \left( {a_0  - a_1 } \right) + \left( {a_2  - a_3 } \right) + \ldots + \left( {a_{2n}  - a_{2n+1} } \right). Every sum in brackets is non-negative. Therefore, the series S2n + 1 is monotonically increasing: for any n \in N the following holds: S_{2n+1}  \le S_{2n + 3} .

From the two paragraphs it follows by the monotone convergence theorem that there exists such a number s that \lim_{n \to \infty } S_{2n+1}  = s.

As S2n = S2n + 1a2n + 1 and as \lim_{n \to  + \infty } a_n  = 0, then \lim_{n \to \infty } S_{2n}  = s. The sum of the given series is \lim_{n \to \infty}S_{2n}  = \lim_{n \to \infty}S_{2n + 1}  = s, where s is a finite number. Thus, convergence is proved.

[edit] Proof of partial sum error

In the proof of convergence we saw that S2n + 1 is monotonically increasing. Since S_{2n} = a_0 +\left(-a_1 + a_2\right) + \ldots + \left(-a_{2n-1} + a_{2n}\right), and every term in brackets is non-positive, we see that S2n is monotonically decreasing. By the previous paragraph, \lim_{n \to \infty}S_{2n} = L, hence S_{2n} \geq L. Similarly, since S2n + 1 is monotonically increasing and converging to L, we have S_{2n+1} \leq L. Hence we have S_{2n+1} \leq L \leq S_{2n} for all n.

Therefore if k is odd we have |L - S_k| = L - S_k \leq S_{k+1} - S_k = a_{k+1} \leq a_k, and if k is even we have |L-S_k| = S_k - L \leq S_k - S_{k-1} = a_k.

[edit] See also

[edit] Literature

  • Knopp, Konrad, "Infinite Sequences and Series", Dover publications, Inc., New York, 1956. (§ 3.4) ISBN 0-486-60153-6
  • Whittaker, E. T., and Watson, G. N., A Course in Modern Analysis, fourth edition, Cambridge University Press, 1963. (§ 2.3) ISBN 0-521-58807-3
  • Last, Philip, "Sequences and Series", New Science, Dublin, 1979. (§ 3.4) ISBN 0-286-53154-3

[edit] References

  1. ^ Beklemishev, Dmitry V. (2005). Analytic geometry and linear algebra course (10 ed.). FIZMATLIT.