# Derivation (differential algebra)

(Redirected from Antiderivation)

In mathematics, a derivation is a function on an algebra which generalizes certain features of the derivative operator. Specifically, given an algebra A over a ring or a field K, a K-derivation is a K-linear map DA → A that satisfies Leibniz's law:

$D(ab) = (Da)b + a(Db).$

More generally, if M is an A-module, a K-linear map D:AM which satisfies the Leibniz law is also called a derivation. The collection of all K-derivations of A to itself is denoted by DerK(A). The collection of K-derivations of A into an A-module M is denoted by DerK(A,M).

Derivations occur in many different contexts in diverse areas of mathematics. The partial derivative with respect to a variable is an R-derivation on the algebra of real-valued differentiable functions on Rn. The Lie derivative with respect to a vector field is an R-derivation on the algebra of differentiable functions on a differentiable manifold; more generally it is a derivation on the tensor algebra of a manifold. The Pincherle derivative is an example of a derivation in abstract algebra. If the algebra A is noncommutative, then the commutator with respect to an element of the algebra A defines a linear endomorphism of A to itself, which is a derivation over K. An algebra A equipped with a distinguished derivation d forms a differential algebra, and is itself a significant object of study in areas such as differential Galois theory.

## Properties

The Leibniz law itself has a number of immediate consequences. Firstly, if x1x2, … ,xn ∈ A, then it follows by mathematical induction that

$D(x_1x_2\cdots x_n) = \sum_i x_1\cdots x_{i-1}D(x_i)x_{i+1}\cdots x_n = \sum_i D(x_i)\prod_{j\neq i}x_j. \,$

In particular, if A is commutative and x1 = x2 = … = xn, then this formula simplifies to the familiar power rule D(xn) = nxn−1D(x). Secondly, if A has a unit element 1, then D(1) = 0 since D(1) = D(1·1) = D(1) + D(1). Moreover, because D is K-linear, it follows that “the derivative of any constant function is zero”; more precisely, for any x ∈ K, D(x) = D(x·1) = x·D(1) = 0.

If k ⊂ K is a subring, and A is a k-algebra, then there is an inclusion

$\operatorname{Der}_K(A,M)\subset \operatorname{Der}_k(A,M),\,$

since any K-derivation is a fortiori a k-derivation.

The set of k-derivations from A to M, Derk(A,M) is a module over k. Furthermore, the k-module Derk(A) forms a Lie algebra with Lie bracket defined by the commutator:

$[D_1,D_2] = D_1\circ D_2 - D_2\circ D_1.$

It is readily verified that the Lie bracket of two derivations is again a derivation.

If we have a graded algebra A, and D is a homogeneous linear map of grade d = |D| on A then D is a homogeneous derivation if $\scriptstyle{D(ab)=D(a)b+\epsilon^{|a||D|}aD(b)}$, ε = ±1 acting on homogeneous elements of A. A graded derivation is sum of homogeneous derivations with the same ε.
If the commutator factor ε = 1, this definition reduces to the usual case. If ε = −1, however, then $\scriptstyle{D(ab)=D(a)b+(-1)^{|a|}aD(b)}$, for odd |D|. They are called anti-derivations.