# Area

(Redirected from Area (geometry))
The combined area of these three shapes is approximately 15.57 squares.

Area is a quantity that expresses the extent of a two-dimensional surface or shape, or planar lamina, in the plane. Area can be understood as the amount of material with a given thickness that would be necessary to fashion a model of the shape, or the amount of paint necessary to cover the surface with a single coat.[1] It is the two-dimensional analog of the length of a curve (a one-dimensional concept) or the volume of a solid (a three-dimensional concept).

The area of a shape can be measured by comparing the shape to squares of a fixed size.[2] In the International System of Units (SI), the standard unit of area is the square metre (written as m2), which is the area of a square whose sides are one metre long.[3] A shape with an area of three square metres would have the same area as three such squares. In mathematics, the unit square is defined to have area one, and the area of any other shape or surface is a dimensionless real number.

There are several well-known formulas for the areas of simple shapes such as triangles, rectangles, and circles. Using these formulas, the area of any polygon can be found by dividing the polygon into triangles.[4] For shapes with curved boundary, calculus is usually required to compute the area. Indeed, the problem of determining the area of plane figures was a major motivation for the historical development of calculus.[5]

For a solid shape such as a sphere, cone, or cylinder, the area of its boundary surface is called the surface area.[1][6] Formulas for the surface areas of simple shapes were computed by the ancient Greeks, but computing the surface area of a more complicated shape usually requires multivariable calculus.

Area plays an important role in modern mathematics. In addition to its obvious importance in geometry and calculus, area is related to the definition of determinants in linear algebra, and is a basic property of surfaces in differential geometry.[7] In analysis, the area of a subset of the plane is defined using Lebesgue measure,[8] though not every subset is measurable.[9] In general, area in higher mathematics is seen as a special case of volume for two-dimensional regions.[1]

Area can be defined through the use of axioms, defining it as a function of a collection of certain plane figures to the set of real numbers. It can be proved that such a function exists.

## Formal definition

An approach to defining what is meant by "area" is through axioms. "Area" can be defined as a function from a collection M of special kind of plane figures (termed measurable sets) to the set of real numbers which satisfies the following properties:

• For all S in M, a(S) ≥ 0.
• If S and T are in M then so are ST and ST, and also a(ST) = a(S) + a(T) − a(ST).
• If S and T are in M with ST then TS is in M and a(TS) = a(T) − a(S).
• If a set S is in M and S is congruent to T then T is also in M and a(S) = a(T).
• Every rectangle R is in M. If the rectangle has length h and breadth k then a(R) = hk.
• Let Q be a set enclosed between two step regions S and T. A step region is formed from a finite union of adjacent rectangles resting on a common base, i.e. SQT. If there is a unique number c such that a(S) ≤ c ≤ a(T) for all such step regions S and T, then a(Q) = c.

It can be proved that such an area function actually exists.[10]

## Units

Every unit of length has a corresponding unit of area, namely the area of a square with the given side length. Thus areas can be measured in square metres (m2), square centimetres (cm2), square millimetres (mm2), square kilometres (km2), square feet (ft2), square yards (yd2), square miles (mi2), and so forth.[11] Algebraically, these units can be thought of as the squares of the corresponding length units.

The SI unit of area is the square metre, which is considered an SI derived unit.[3]

### Conversions

Although there are 10 mm in 1 cm, there are 100 mm2 in 1 cm2.

The conversion between two square units is the square of the conversion between the corresponding length units. For example, since

1 foot = 12 inches,

the relationship between square feet and square inches is

1 square foot = 144 square inches,

where 144 = 122 = 12 × 12. Similarly:

• 1 square kilometer = 1,000,000 square meters
• 1 square meter = 10,000 square centimetres = 1,000,000 square millimetres
• 1 square centimetre = 100 square millimetres
• 1 square yard = 9 square feet
• 1 square mile = 3,097,600 square yards = 27,878,400 square feet

• 1 square inch = 6.4516 square centimetres
• 1 square foot = 0.09290304 square metres
• 1 square yard = 0.83612736 square metres
• 1 square mile = 2.589988110336 square kilometres

### Other units

There are several other common units for area. The "Are" was the original unit of area in the metric system, with;

• 1 are = 100 square metres

Though the are has fallen out of use, the hectare is still commonly used to measure land:[11]

• 1 hectare = 100 ares = 10,000 square metres = 0.01 square kilometres

The acre is also commonly used to measure land areas, where

• 1 acre = 4,840 square yards = 43,560 square feet.

An acre is approximately 40% of a hectare.

On the atomic scale, area is measured in units of barns, such that:[11]

• 1 barn = 10−28 square meters.

The barn is commonly used in describing the cross sectional area of interaction in nuclear physics.[11]

In India,

• 20 Dhurki = 1 Dhur
• 20 Dhur = 1 Khatha
• 20 Khata = 1 Bigha
• 32 Khata = 1 Acre

## Area formulae

### Polygon formulae

#### Rectangles

The area of this rectangle is lw.

The most basic area formula is the formula for the area of a rectangle. Given a rectangle with length l and width w, the formula for the area is:[2]

A = lw (rectangle)

That is, the area of the rectangle is the length multiplied by the width. As a special case, as l = w in the case of a square, the area of a square with side length s is given by the formula:[1][2]

A = s2 (square)

The formula for the area of a rectangle follows directly from the basic properties of area, and is sometimes taken as a definition or axiom. On the other hand, if geometry is developed before arithmetic, this formula can be used to define multiplication of real numbers.

Equal area figures.

#### Dissection formulae

Most other simple formulae for area follow from the method of dissection. This involves cutting a shape into pieces, whose areas must sum to the area of the original shape.

For an example, any parallelogram can be subdivided into a trapezoid and a right triangle, as shown in figure to the left. If the triangle is moved to the other side of the trapezoid, then the resulting figure is a rectangle. It follows that the area of the parallelogram is the same as the area of the rectangle:[2]

A = bh  (parallelogram).
Two equal triangles.

However, the same parallelogram can also be cut along a diagonal into two congruent triangles, as shown in the figure to the right. It follows that the area of each triangle is half the area of the parallelogram:[2]

$A = \frac{1}{2}bh$  (triangle).

Similar arguments can be used to find area formulae for the trapezoid and the rhombus, as well as more complicated polygons.[citation needed]

### Area of curved shapes

#### Circles

A circle can be divided into sectors which rearrange to form an approximate parallelogram.

The formula for the area of a circle (more properly called area of a disk) is based on a similar method. Given a circle of radius r, it is possible to partition the circle into sectors, as shown in the figure to the right. Each sector is approximately triangular in shape, and the sectors can be rearranged to form and approximate parallelogram. The height of this parallelogram is r, and the width is half the circumference of the circle, or πr. Thus, the total area of the circle is r × πr, or πr2:[2]

A = πr2  (circle).

Though the dissection used in this formula is only approximate, the error becomes smaller and smaller as the circle is partitioned into more and more sectors. The limit of the areas of the approximate parallelograms is exactly πr2, which is the area of the circle.[12]

This argument is actually a simple application of the ideas of calculus. In ancient times, the method of exhaustion was used in a similar way to find the area of the circle, and this method is now recognized as a precursor to integral calculus. Using modern methods, the area of a circle can be computed using a definite integral:

$A \;=\; \int_{-r}^r 2\sqrt{r^2 - x^2}\,dx \;=\; \pi r^2$

#### Ellipses

The formula for the area of an ellipse is related to the formula of a circle; for an ellipse with semi-major and semi-minor axes x and y the formula is:[2]

$A = \pi xy \,\!$

#### Surface area

Archimedes showed that the surface area and volume of a sphere is exactly 2/3 of the area and volume of the surrounding cylindrical surface.

Most basic formulae for surface area can be obtained by cutting surfaces and flattening them out. For example, if the side surface of a cylinder (or any prism) is cut lengthwise, the surface can be flattened out into a rectangle. Similarly, if a cut is made along the side of a cone, the side surface can be flattened out into a sector of a circle, and the resulting area computed.

The formula for the surface area of a sphere is more difficult to derive: because a sphere has nonzero Gaussian curvature, it cannot be flattened out. The formula for the surface area of a sphere was first obtained by Archimedes in his work On the Sphere and Cylinder. The formula is:[6]

A = 4πr2  (sphere).

where r is the radius of the sphere. As with the formula for the area of a circle, any derivation of this formula inherently uses methods similar to calculus.

### General formulae

#### Areas of 2-dimensional figures

• A triangle: $\tfrac12Bh$ (where B is any side, and h is the distance from the line on which B lies to the other vertex of the triangle). This formula can be used if the height h is known. If the lengths of the three sides are known then Heron's formula can be used: $\sqrt{s(s-a)(s-b)(s-c)}$ where a, b, c are the sides of the triangle, and $s = \tfrac12(a + b + c)$ is half of its perimeter.[2] If an angle and its two included sides are given, the area is $\tfrac12 a b \sin(C)$ where C is the given angle and a and b are its included sides.[2] If the triangle is graphed on a coordinate plane, a matrix can be used and is simplified to the absolute value of $\tfrac12(x_1 y_2 + x_2 y_3 + x_3 y_1 - x_2 y_1 - x_3 y_2 - x_1 y_3)$. This formula is also known as the shoelace formula and is an easy way to solve for the area of a coordinate triangle by substituting the 3 points (x1,y1), (x2,y2), and (x3,y3). The shoelace formula can also be used to find the areas of other polygons when their vertices are known. Another approach for a coordinate triangle is to use Infinitesimal calculus to find the area.
• A simple polygon constructed on a grid of equal-distanced points (i.e., points with integer coordinates) such that all the polygon's vertices are grid points: $i + \frac{b}{2} - 1$, where i is the number of grid points inside the polygon and b is the number of boundary points.[13] This result is known as Pick's theorem.[13]

#### Area in calculus

Integration can be thought of as measuring the area under a curve, defined by f(x), between two points (here a and b).
The area between two graphs can be evaluated by calculating the difference between the integrals of the two functions
• The area between a positive-valued curve and the horizontal axis, measured between two values a and b (b is defined as the larger of the two values) on the horizontal axis, is given by the integral from a to b of the function that represents the curve:[1]
$A = \int_a^{b} f(x) \, dx$
$A = \int_a^{b} ( f(x) - g(x) ) \, dx$ where $f(x)$ is the curve with the greater y-value.
$A = {1 \over 2} \int r^2 \, d\theta$
• The area enclosed by a parametric curve $\vec u(t) = (x(t), y(t))$ with endpoints $\vec u(t_0) = \vec u(t_1)$ is given by the line integrals:
$\oint_{t_0}^{t_1} x \dot y \, dt = - \oint_{t_0}^{t_1} y \dot x \, dt = {1 \over 2} \oint_{t_0}^{t_1} (x \dot y - y \dot x) \, dt$

(see Green's theorem) or the z-component of

${1 \over 2} \oint_{t_0}^{t_1} \vec u \times \dot{\vec u} \, dt.$

#### Surface area of 3-dimensional figures

• cone:[14] $\pi r\left(r + \sqrt{r^2 + h^2}\right)$, where r is the radius of the circular base, and h is the height. That can also be rewritten as $\pi r^2 + \pi r l$[14] or $\pi r (r + l) \,\!$ where r is the radius and l is the slant height of the cone. $\pi r^2$ is the base area while $\pi r l$ is the lateral surface area of the cone.[14]
• cube: $6s^2$, where s is the length of an edge.[6]
• cylinder: $2\pi r(r + h)$, where r is the radius of a base and h is the height. The 2$\pi$r can also be rewritten as $\pi$ d, where d is the diameter.
• prism: 2B + Ph, where B is the area of a base, P is the perimeter of a base, and h is the height of the prism.
• pyramid: $B + \frac{PL}{2}$, where B is the area of the base, P is the perimeter of the base, and L is the length of the slant.
• rectangular prism: $2 (\ell w + \ell h + w h)$, where $\ell$ is the length, w is the width, and h is the height.

#### General formula

The general formula for the surface area of the graph of a continuously differentiable function $z=f(x,y),$ where $(x,y)\in D\subset\mathbb{R}^2$ and $D$ is a region in the xy-plane with the smooth boundary:

$A=\iint_D\sqrt{\left(\frac{\partial f}{\partial x}\right)^2+\left(\frac{\partial f}{\partial y}\right)^2+1}\,dx\,dy.$

Even more general formula for the area of the graph of a parametric surface in the vector form $\mathbf{r}=\mathbf{r}(u,v),$ where $\mathbf{r}$ is a continuously differentiable vector function of $(u,v)\in D\subset\mathbb{R}^2$:[7]

$A=\iint_D \left|\frac{\partial\mathbf{r}}{\partial u}\times\frac{\partial\mathbf{r}}{\partial v}\right|\,du\,dv.$

### List of formulas

There are formulae for many different regular and irregular polygons, and those additional to the ones above are listed here.

Shape Formula Variables
Regular triangle (equilateral triangle) $\frac{\sqrt{3}}{4}s^2\,\!$ $s$ is the length of one side of the triangle.
Triangle[1] $\sqrt{s(s-a)(s-b)(s-c)}\,\!$ $s$ is half the perimeter, $a$, $b$ and $c$ are the length of each side.
Triangle[2] $\tfrac12 a b \sin(C)\,\!$ $a$ and $b$ are any two sides, and $C$ is the angle between them.
Triangle[1] $\tfrac12bh \,\!$ $b$ and $h$ are the base and altitude (measured perpendicular to the base), respectively.
Isosceles triangle $\frac{1}{2}b\sqrt{a^2-\frac{b^2}{4}}$ $a$ is the length of an equal side and $b$ is the length of a different side.
Rhombus $\tfrac12ab$ $a$ and $b$ are the lengths of the two diagonals of the rhombus.
Parallelogram $bh\,\!$ $b$ is the length of the base and $h$ is the perpendicular height.
Trapezoid $\frac{(a+b)h}{2} \,\!$ $a$ and $b$ are the parallel sides and $h$ the distance (height) between the parallels.
Regular hexagon $\frac{3}{2} \sqrt{3}s^2\,\!$ $s$ is the length of one side of the hexagon.
Regular octagon $2(1+\sqrt{2})s^2\,\!$ $s$ is the length of one side of the octagon.
Regular polygon $\frac{1}{4}nl^2\cdot \cot(\pi/n)\,\!$ $l$ is the side length and $n$ is the number of sides.
Regular polygon $\frac{1}{4n}p^2\cdot \cot(\pi/n)\,\!$ $p$ is the perimeter and $n$ is the number of sides.
Regular polygon $\frac{1}{2}nR^2\cdot \sin(2\pi/n) = nr^2 \tan(\pi/n)\,\!$ $R$ is the radius of a circumscribed circle, $r$ is the radius of an inscribed circle, and $n$ is the number of sides.
Regular polygon $\tfrac12 ap = \tfrac12 nsa \,\!$ $n$ is the number of sides, $s$ is the side length, $a$ is the apothem, or the radius of an inscribed circle in the polygon, and $p$ is the perimeter of the polygon.
Circle $\pi r^2\ \text{or}\ \frac{\pi d^2}{4} \,\!$ $r$ is the radius and $d$ the diameter.
Circular sector $\frac{\theta}{2}r^2\ \text{or}\ \frac{L \cdot r}{2}\,\!$ $r$ and $\theta$ are the radius and angle (in radians), respectively and $L$ is the length of the perimeter.
Ellipse[2] $\pi ab \,\!$ $a$ and $b$ are the semi-major and semi-minor axes, respectively.
Total surface area of a cylinder $2\pi r (r + h)\,\!$ $r$ and $h$ are the radius and height, respectively.
Lateral surface area of a cylinder $2 \pi r h \,\!$ $r$ and $h$ are the radius and height, respectively.
Total surface area of a sphere[6] $4\pi r^2\ \text{or}\ \pi d^2\,\!$ $r$ and $d$ are the radius and diameter, respectively.
Total surface area of a pyramid[6] $B+\frac{P L}{2}\,\!$ $B$ is the base area, $P$ is the base perimeter and $L$ is the slant height.
Total surface area of a pyramid frustum[6] $B+\frac{P L}{2}\,\!$ $B$ is the base area, $P$ is the base perimeter and $L$ is the slant height.
Square to circular area conversion $\frac{4}{\pi} A\,\!$ $A$ is the area of the square in square units.
Circular to square area conversion $\frac{1}{4} C\pi\,\!$ $C$ is the area of the circle in circular units.
Reuleaux Triangle $\frac{\pi x^2}{6}-\frac{3 \sqrt{x^2-(\frac{x}{2})^2}}{2}+\frac{\sqrt{x^2-(\frac{x}{2})^2}}{2}$ $x$ is the side of the triangle inside the reuleaux triangle.

The above calculations show how to find the area of many common shapes.

The areas of irregular polygons can be calculated using the "Surveyor's formula".[12]

## Optimization

Given a wire contour, the surface of least area spanning ("filling") it is a minimal surface. Familiar examples include soap bubbles.

The question of the filling area of the Riemannian circle remains open.[citation needed]

## References

1. Eric W. Weisstein. "Area". Wolfram MathWorld. Retrieved 3 July 2012.
2. "Area Formulas". Math.com. Retrieved 2 July 2012.
3. ^ a b Bureau International des Poids et Mesures Resolution 12 of the 11th meeting of the CGPM (1960), retrieved 15 July 2012
4. ^ Mark de Berg; Marc van Kreveld; Mark Overmars; Otfried Schwarzkopf (2000). "Chapter 3: Polygon Triangulation". Computational Geometry (2nd revised ed.). Springer-Verlag. pp. 45–61. ISBN 3-540-65620-0
5. ^ Boyer, Carl B. (1959). A History of the Calculus and Its Conceptual Development. Dover. ISBN 0-486-60509-4.
6. Eric W. Weisstein. "Surface Area". Wolfram MathWorld. Retrieved 3 July 2012.
7. ^ a b do Carmo, Manfredo. Differential Geometry of Curves and Surfaces. Prentice-Hall, 1976. Page 98, ISBN 978-0-13-212589-5
8. ^ Walter Rudin, Real and Complex Analysis, McGraw-Hill, 1966, ISBN 0-07-100276-6.
9. ^ Gerald Folland, Real Analysis: modern techniques and their applications, John Wiley & Sons, Inc., 1999,Page 20,ISBN 0-471-31716-0
10. ^ Moise, Edwin (1963). Elementary Geometry from an Advanced Standpoint. Addison-Wesley Pub. Co. Retrieved 15 July 2012.
11. ^ a b c d Bureau international des poids et mesures (2006). The International System of Units (SI). 8th ed. Retrieved 2008-02-13. Chapter 5.
12. ^ a b Braden, Bart (September 1986). "The Surveyor's Area Formula". The College Mathematics Journal 17 (4): 326–337. doi:10.2307/2686282. Retrieved 15 July 2012.
13. ^ a b Trainin, J. (November 2007). "An elementary proof of Pick's theorem". Mathematical Gazette 91 (522): 536–540.
14. ^ a b c Eric W. Weisstein. "Cone". Wolfram MathWorld. Retrieved 6 July 2012.