Ashland, Indiana
From Wikipedia, the free encyclopedia
| Ashland | |
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| — Unincorporated town — | |
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| Coordinates: 39°55′34″N 85°18′16″W / 39.92611°N 85.30444°WCoordinates: 39°55′34″N 85°18′16″W / 39.92611°N 85.30444°W | |
| Country | United States |
| State | Indiana |
| County | Henry |
| Township | Liberty |
| Elevation | 1,112 ft (339 m) |
| ZIP code | 47362 |
| FIPS code | 18-02422[1] |
| GNIS feature ID | 430310[2] |
Ashland is an unincorporated town in Liberty Township, Henry County, Indiana.
[edit] Geography
Ashland is located at 39°55′34″N 85°18′16″W / 39.92611°N 85.30444°W.
[edit] References
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
- ^ "Ashland, Indiana". Geographic Names Information System, U.S. Geological Survey. http://geonames.usgs.gov/pls/gnispublic/f?p=gnispq:3:::NO::P3_FID:430310. Retrieved 2009-10-10.
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