Buzescu
From Wikipedia, the free encyclopedia
| Buzescu | |
|---|---|
| — Commune — | |
 |
|
| Coordinates: 44°01′N 25°14′E / 44.017°N 25.233°ECoordinates: 44°01′N 25°14′E / 44.017°N 25.233°E | |
| Country | Romania |
| County | Teleorman |
| Component villages | Buzescu |
| Government | |
| • Mayor | Valenitn Trăistaru (since 2004) (PNL) |
| Area | |
| • Total | 35 km2 (13.5 sq mi) |
| Population (2007) | |
| • Total | 4,700 |
| • Density | 134.3/km2 (347.8/sq mi) |
| Postal code | |
Buzescu is a commune in Teleorman County, Romania. It is composed of a single village, Buzescu.
At the 2002 census, 77% of inhabitants were Romanians and 22.9% Roma. 94.9% were Romanian Orthodox and 4.7% Seventh-day Adventist.
[edit] References
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