Cape Sandy, Indiana
From Wikipedia, the free encyclopedia
| Cape Sandy | |
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| — Town — | |
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| Coordinates: 38°09′03″N 86°22′15″W / 38.15083°N 86.37083°WCoordinates: 38°09′03″N 86°22′15″W / 38.15083°N 86.37083°W | |
| Country | United States |
| State | Indiana |
| County | Crawford |
| Township | Ohio |
| Elevation | 741 ft (226 m) |
| ZIP code | 47137 |
| FIPS code | 18-10180[1] |
| GNIS feature ID | 432118[2] |
Cape Sandy is an unincorporated community in Ohio Township, Crawford County, Indiana.
[edit] Geography
Cape Sandy is located at 38°09′03″N 86°22′15″W / 38.15083°N 86.37083°W.
[edit] References
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
- ^ "Cape Sandy, Indiana". Geographic Names Information System, U.S. Geological Survey. http://geonames.usgs.gov/pls/gnispublic/f?p=gnispq:3:::NO::P3_FID:432118. Retrieved 2009-10-10.
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[edit] See also
| This Crawford County, Indiana location article is a stub. You can help Wikipedia by expanding it. |