Cleveland, Indiana
From Wikipedia, the free encyclopedia
| Cleveland | |
|---|---|
| — Town — | |
 Cleveland
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| Coordinates: 39°47′25″N 85°38′41″W / 39.79028°N 85.64472°WCoordinates: 39°47′25″N 85°38′41″W / 39.79028°N 85.64472°W | |
| Country | United States |
| State | Indiana |
| County | Hancock |
| Township | Jackson |
| Elevation | 971 ft (296 m) |
| ZIP code | 46140 |
| FIPS code | 18-13546[1] |
| GNIS feature ID | 432645[2] |
Cleveland is an unincorporated town in Jackson Township, Hancock County, Indiana.
[edit] Geography
Cleveland is located at 39°47′25″N 85°38′41″W / 39.79028°N 85.64472°W.
[edit] References
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
- ^ "Cleveland, Indiana". Geographic Names Information System, U.S. Geological Survey. http://geonames.usgs.gov/pls/gnispublic/f?p=gnispq:3:::NO::P3_FID:432645. Retrieved 2009-10-10.
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