Clinton Township, Shelby County, Ohio

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Clinton Township, Ohio
Coordinates: 40°17′17″N 84°9′43″W / 40.28806°N 84.16194°W / 40.28806; -84.16194Coordinates: 40°17′17″N 84°9′43″W / 40.28806°N 84.16194°W / 40.28806; -84.16194
Country United States
State Ohio
County Shelby
 • Total 16.7 sq mi (43.4 km2)
 • Land 16.7 sq mi (43.2 km2)
 • Water 0.1 sq mi (0.2 km2)
Elevation[1] 1,037 ft (316 m)
Population (2000)
 • Total 20,903
 • Density 1,254.5/sq mi (484.4/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 39-16168[2]
GNIS feature ID 1086958[1]
Municipalities, townships, and waterways of Shelby County.

Clinton Township is one of the fourteen townships of Shelby County, Ohio, United States. The 2000 census found 20,903 people in the township, 1,223 of whom lived in the unincorporated portions of the township.[3]


Located in the southern part of the county, it borders the following townships:

Most of Clinton Township is occupied by the city of Sidney, the county seat of Shelby County.


It is one of seven Clinton Townships statewide.[4]


The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[5] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.


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