Collision resistance

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Collision resistance is a property of cryptographic hash functions: a hash function is collision resistant if it is hard to find two inputs that hash to the same output; that is, two inputs a and b such that H(a) = H(b), and ab.[1]:136

Every hash function with more inputs than outputs will necessarily have collisions. [1]:136Consider a hash function such as SHA-256 that produces 256 bits of output from an arbitrarily large input. Since it must generate one of 2256 outputs for each member of a much larger set of inputs, the pigeonhole principle guarantees that some inputs will hash to the same output. Collision resistance doesn't mean that no collisions exist; simply that they are hard to find.[1]:143

The "birthday paradox" places an upper bound on collision resistance: if a hash function produces N bits of output, an attacker who computes "only" 2N/2 (or \scriptstyle \sqrt{ 2^N}) hash operations on random input is likely to find two matching outputs. If there is an easier method than this brute force attack, it is typically considered a flaw in the hash function.[2]

Cryptographic hash functions are usually designed to be collision resistant. But many hash functions that were once thought to be collision resistant were later broken. MD5 and SHA-1 in particular both have published techniques more efficient than brute force for finding collisions.[3][4] However, some hash functions have a proof that finding collisions is at least as difficult as some hard mathematical problem (such as integer factorization or discrete logarithm). Those functions are called provably secure.[2]

Rationale[edit]

Collision resistance is desirable for several reasons.

  • In some digital signature systems, a party attests to a document by publishing a public key signature on a hash of the document. If it is possible to produce two documents with the same hash, an attacker could get a party to attest to one, and then claim that the party had attested to the other.
  • In some proof-of-work systems, users provide hash collisions as proof that they have performed a certain amount of computation to find them. If there is an easier way to find collisions than brute force, users can cheat the system.
  • In some distributed content systems, parties compare cryptographic hashes of files in order to make sure they have the same version. An attacker who could produce two files with the same hash could trick users into believing they had the same version of a file when they in fact did not.

See also[edit]

References[edit]

  1. ^ a b c Goldwasser, S. and Bellare, M. "Lecture Notes on Cryptography". Summer course on cryptography, MIT, 1996-2001
  2. ^ a b Pass, R. "Lecture 21: Collision-Resistant Hash Functions and General Digital Signature Scheme". Course on Cryptography, Cornell University, 2009
  3. ^ Xiaoyun Wang and Hongbo Yu. "How to Break MD5 and Other Hash Functions". Retrieved 2009-12-21. 
  4. ^ Xiaoyun Wang, Yiquin Lisa Yin, Hongobo Yu. Finding Collisions in the Full SHA-1.