Delaware Township, Ripley County, Indiana

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Delaware Township
Township
Map highlighting Delaware Township, Ripley County, Indiana.svg
Coordinates: 39°10′50″N 85°14′52″W / 39.18056°N 85.24778°W / 39.18056; -85.24778Coordinates: 39°10′50″N 85°14′52″W / 39.18056°N 85.24778°W / 39.18056; -85.24778
Country United States
State Indiana
County Ripley
Government
 • Type Indiana township
Area
 • Total 33.27 sq mi (86.2 km2)
 • Land 33.21 sq mi (86.0 km2)
 • Water 0.06 sq mi (0.2 km2)
Elevation[1] 928 ft (283 m)
Population (2010)
 • Total 1,437
 • Density 43.3/sq mi (16.7/km2)
FIPS code 18-17524[2]
GNIS feature ID 453262

Delaware Township is one of eleven townships in Ripley County, Indiana. As of the 2010 census, its population was 1,437 and it contained 578 housing units.[3]

Geography[edit]

According to the 2010 census, the township has a total area of 33.27 square miles (86.2 km2), of which 33.21 square miles (86.0 km2) (or 99.82%) is land and 0.06 square miles (0.16 km2) (or 0.18%) is water.[3]

References[edit]

  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31. 
  2. ^ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31. 
  3. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10. 

External links[edit]