Douglas, Indiana
From Wikipedia, the free encyclopedia
| Douglas | |
|---|---|
| — Town — | |
 Douglas
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| Coordinates: 38°19′50″N 87°30′06″W / 38.33056°N 87.50167°WCoordinates: 38°19′50″N 87°30′06″W / 38.33056°N 87.50167°W | |
| Country | United States |
| State | Indiana |
| County | Gibson |
| Township | Center |
| Elevation | 472 ft (144 m) |
| ZIP code | 47649 |
| FIPS code | 18-18496[1] |
| GNIS feature ID | 433652[2] |
Douglas is an unincorporated community in Center Township, Gibson County, Indiana.
[edit] Geography
Douglas is located at 38°19′50″N 87°30′06″W / 38.33056°N 87.50167°W.
[edit] References
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
- ^ "Douglas, Indiana". Geographic Names Information System, U.S. Geological Survey. http://geonames.usgs.gov/pls/gnispublic/f?p=gnispq:3:::NO::P3_FID:433652. Retrieved 2009-10-10.
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