Foot-pound (energy)

(Redirected from Feet-pound-force)
Not to be confused with Pound-foot (torque) or Foot-poundal.

The foot-pound force (symbol: ft·lbf or ft·lbf), or simply foot-pound (symbol: ft·lb) is a unit of work or energy in the Engineering and Gravitational Systems in United States customary and imperial units of measure. It is the energy transferred on applying a force of one pound-force (lbf) through a displacement of one foot. The corresponding SI unit is the joule.

Usage

The foot-pound is often used to specify the muzzle energy of a bullet in small arms ballistics, particularly in the United States.

"Foot-pound" is sometimes also used as a unit of torque (see Pound-foot (torque)). In the United States this unit is often used to specify, for example, the tightness of a bolt or the output of an engine. Although they are dimensionally equivalent, energy (a scalar), and torque (a vector) are distinct physical quantities. Both energy and torque can be expressed as a product of a force vector with a displacement vector (hence pounds and feet); energy is the scalar product of the two, and torque is the vector product.

Conversion to other units

Energy units

1 foot-pound is equivalent to:

Power units

• 1 watt44.25372896 ft·lbf/min = 0.737562149333 ft·lbf/sec
• 1 horsepower (mechanical) = 33,000 ft·lbf/min = 550 ft·lbf/s