Fountaintown, Indiana
From Wikipedia, the free encyclopedia
| Fountaintown | |
|---|---|
| — Town — | |
 Fountaintown
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| Coordinates: 39°41′41″N 85°46′59″W / 39.69472°N 85.78306°WCoordinates: 39°41′41″N 85°46′59″W / 39.69472°N 85.78306°W | |
| Country | United States |
| State | Indiana |
| County | Shelby |
| Township | Van Buren |
| Elevation | 850 ft (260 m) |
| ZIP code | 46130 |
| FIPS code | 18-25162[1] |
| GNIS feature ID | 434718[2] |
Fountaintown is an unincorporated town in Van Buren Township, Shelby County, Indiana.
[edit] Geography
Fountaintown is located at 39°41′41″N 85°46′59″W / 39.69472°N 85.78306°W.
[edit] References
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
- ^ "Fountaintown, Indiana". Geographic Names Information System, U.S. Geological Survey. http://geonames.usgs.gov/pls/gnispublic/f?p=gnispq:3:::NO::P3_FID:434718. Retrieved 2009-10-17.
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