# Free carrier absorption

Free carrier absorption occurs when a material absorbs a photon and a carrier (electron or hole) is excited from an already-excited state to another, unoccupied state in the same band (but possibly a different subband). This is different from interband absorption because the excited carrier is already in an exited band, such as electrons in the conduction band or holes in the valence band, where it is free to move. In interband absorption, the carrier would start in a fixed, nonconducting band and be excited to a conducting one.

It is well known that the optical transition of electrons and holes in the solid state is a useful clue to understand the physical properties of the material. However, the dynamics of the carrier are affected by other carriers and not only by the periodic lattice potential. Moreover, the thermal fluctuation of each electron should be taken into account. Therefore a statistical approach is needed. To predict the optical transition in an appropriate precession, one should choose an approximation, called assumption of quasi-thermal distributions, of the electrons in the conduction band and of the holes in the valence band. In this case, the diagonal components of the density matrix become negligible after introducing the thermal distribution function,

$\rho _{\lambda \lambda }^0 = \frac{1}{{e^{(\varepsilon _{\lambda ,k} - \mu )\beta } + 1}} = f_{\lambda ,k}$

This is the famous Fermi-Dirac distribution for the distribution of electrons energies $\varepsilon$. Thus, summing over possible all possible states (l and k) yields the total number of carriers N.

$N_\lambda = \sum\limits_\lambda {f_{\lambda ,k}}$

## The optical susceptibility

Using the above distribution function, the time evolution of the density matrix can be ignored, which greatly simplifies the analysis.

$\rho _{cv}^{{\mathop{\rm int}} } (k,t) = \int {\frac{{d\omega }}{{2\pi }}\frac{{d_{cv} \varepsilon (\omega )e^{i(\varepsilon _{c,k} - \varepsilon _{v,k} - \omega )t} }}{{\hbar (\varepsilon _{c,k} - \varepsilon _{v,k} - \omega - i\gamma )}}(f_{v,k} - f_{c,k} )}$

The optical polarization is,

$\displaystyle P(t) = tr[\rho (t)d]$

With this relation and after adjusting the Fourier transformation, the optical susceptibility is $\chi (\omega ) = - \sum\limits_k {\frac{{\left| {d_{cv} } \right|^{_2 } }}{{L^3 }}} (f_{v,k} - f_{c,k})\left( {\frac{1}{{\hbar (\varepsilon _{v,k} - \varepsilon _{c,k}+ \omega + i\gamma )}} - \frac{1}{{\hbar (\varepsilon _{c,k} - \varepsilon _{v,k} + \omega + i\gamma )}}} \right)$

## Absorption coefficient

The transition amplitude corresponds to the absorption of energy and the absorbed energy is proportional to the optical conductivity which is the imaginary part of the optical susceptibility after frequency is multiplied. Therefore, in order to obtain the absorption coefficient that is crucial quantity for investigation of electronic structure, we can use the optical susceptibility.

$\alpha (\omega ) = \frac{{4\pi \omega }}{{n_b c}}\chi ''(\omega )$

${\rm{ }} = \frac{{4\pi \omega }}{{n_b c}}\sum\limits_k {\left| {d_{cv} } \right|^2 (f_{v,k} - f_{c,k} )\delta (\hbar (\varepsilon _{v,k} - \varepsilon _{c,k} + \omega ))}$

The energy of free carriers is proportional to the square of momentum (E~k2). Using the band gap energy Eg and the electron-hole distribution function, we can obtain the absorption coefficient with some mathematical calculation. The final result is $\alpha (\omega ) = \alpha _0^d \frac{{\hbar \omega }}{{E_0 }}\left( {\frac{{\hbar \omega - E_g - E_0^{(d)} }}{{E_0 }}} \right)^{(d - 2)/2} \sum\limits_k {\Theta (\hbar \omega - E_g - E_0^{(d)} )A(\omega )}$

This result is important to understand the optical measurement data and the electronic properties of metals and semiconductors. It is worth noting that the absorption coefficient is negative when the material supports stimulated emission, which is the basis for the operation of lasers, particularly semiconductor laser.

## References

1. H. Haug and S. W. Koch, "[1] ", World Scientific (1994). sec.5.4 a