# Fugacity

In chemical thermodynamics, the fugacity ($f$) of a real gas is an effective pressure which replaces the true mechanical pressure in accurate chemical equilibrium calculations. It is equal to the pressure of an ideal gas which has the same chemical potential as the real gas. For example, nitrogen gas (N2) at 0°C and a pressure of $P=100\,\rm atm$ has a fugacity of $f=97.03\,\rm atm$.[1] This means that the chemical potential of real nitrogen at a pressure of 100 atm is less than if nitrogen were an ideal gas; the value of the chemical potential is that which nitrogen as an ideal gas would have at a pressure of 97.03 atm

Fugacities are determined experimentally or estimated from various models such as a Van der Waals gas that are closer to reality than an ideal gas. The ideal gas pressure and fugacity are related through the dimensionless fugacity coefficient $\phi \,$.[2]

$\phi = f/P \,$

For nitrogen at 100 atm, the fugacity coefficient is 97.03 atm / 100 atm = 0.9703. For an ideal gas, fugacity and pressure are equal so $\phi \,$ is 1.

The contribution of nonideality to the chemical potential of a real gas is equal to RT ln $\phi$. Again for nitrogen at 100 atm, the chemical potential is μ = μid + RT ln 0.9703, which is less than the ideal value μid because of intermolecular attractive forces.

The fugacity is closely related to the thermodynamic activity. For a gas, the activity is simply the fugacity divided by a reference pressure to give a dimensionless quantity. This reference pressure is called the standard state and normally chosen as 1 atmosphere or 1 bar, Again using nitrogen at 100 atm as an example, since the fugacity is 97.03 atm, the activity is just 97.03 without units.

Accurate calculations of chemical equilibrium for real gases should use the fugacity rather than the pressure. The thermodynamic condition for chemical equilibrium is that the total chemical potential of reactants is equal to that of products. If the chemical potential of each gas is expressed as a function of fugacity, the equilibrium condition may be transformed into the familiar reaction quotient form (or law of mass action) except that the pressures are replaced by fugacities.

For a condensed phase (liquid or solid) in equilibrium with its vapor phase, the chemical potential is equal to that of the vapor, and therefore the fugacity is equal to the fugacity of the vapor. This fugacity is approximately equal to the vapor pressure when the vapor pressure is not too high.

The word "fugacity" is derived from the Latin for "fleetness", which is often interpreted as "the tendency to flee or escape". The concept of fugacity was introduced by American chemist Gilbert N. Lewis in 1901.[3]

## Definition in terms of chemical potential

The fugacity of a real gas is formally defined by an equation analogous to the relation between the chemical potential and the pressure of an ideal gas.

In general, the chemical potential (μ) is defined as the partial molar Gibbs free energy. However, for any pure substance it is equal to the molar Gibbs free energy, and its variation with temperature (T) and pressure (P) is given by ${d\mu } = dG = -SdT + VdP$. At constant temperature, this expression can be integrated as a function of $P$. We must also set a reference state. For an ideal gas the reference state depends only on pressure, and we set $P$ = 1 bar so that

$\int_{\mu^\circ }^\mu {d\mu } = \int_{P^\circ }^P {\bar VdP}$

Now, for an ideal gas $\bar V = \frac{{RT}}{P}$

$\mu - \mu ^\circ = \int_{P^\circ }^P {\frac{{RT}} {P}dP} = RT\ln \frac{P} {{P^\circ }}$

Reordering, we get

$\mu = \mu ^\circ + RT\ln \frac{P} {{P^\circ }}$

This gives the chemical potential for an ideal gas in an isothermal process, with a reference state is $P$ = 1 bar.

For a real gas, the integral $\int_{P^\circ }^P {\bar VdP}$ cannot be calculated because there isn't a simple expression for a real gas's molar volume. Even if using an approximate expression such as the van der Waals equation, the Redlich–Kwong or any other equation of state, it would depend on the substance being studied and would be therefore of very limited utility.

Additionally, chemical potential is not mathematically well behaved. It approaches negative infinity as pressure approaches zero and this creates problems in doing real calculations.

It is desirable that the expression for a real gas’ chemical potential to be similar to the one for an ideal gas. Therefore one can define a quantity, called fugacity, so that the chemical potential for a real gas becomes

$\mu = \mu ^\circ + RT\ln \frac{f} {{f^\circ }}$

with a given reference state to be discussed later. This is the usual form of the definition, but it may be solved for f to obtain the equivalent explicit form

$f = {{f^\circ }} \exp \left(\frac{\mu - \mu ^\circ}{RT}\right)$

## Evaluation of fugacity for a real gas

Fugacity is used to better approximate the chemical potential of real gases than estimations made using the ideal gas law. Yet fugacity allows the use of many of the relationships developed for an idealized system.

In the real world, gases approach ideal gas behavior at low pressures and high temperatures; under such conditions the value of fugacity approaches the value of pressure. Yet no substance is truly ideal. At moderate pressures real gases have attractive interactions and at high pressures intermolecular repulsions become important. Both interactions result in a deviation from "ideal" behavior for which interactions between gas atoms or molecules are ignored.

For a given temperature $T\,$, the fugacity $f\,$ satisfies the following differential relation:

$d \ln {f \over f_0} = {dG \over RT} = {{\bar V dP} \over RT} \,$

where $G\,$ is the Gibbs free energy, $R\,$ is the gas constant, $\bar V\,$ is the fluid's molar volume, and $f_0\,$ is a reference fugacity which is generally taken as 1 bar. For an ideal gas, when $f=P$, this equation reduces to the ideal gas law.

Thus, for any two physical states at the same temperature, represented by subscripts 1 and 2, the ratio of the two fugacities is as follows:

${f_2 \over f_1} = \exp \left ({1 \over RT} \int_{G_1}^{G_2} dG \right) = \exp \left ({1 \over RT} \int_{P_1}^{P_2} \bar V\,dP \right) \,$

For an ideal gas, this becomes simply ${f_2 \over f_1} = {p_2 \over p_1}$ or $f = P$

But for $P \to 0$, every gas is an ideal gas. Therefore, fugacity must obey the limit equation

$\mathop {\lim }_{P \to 0} \frac{f} {P} = 1$

We determine $f$ by defining a new function $\Phi$, which is the difference between the actual molar volume and the ideal-gas molar volume:

$\Phi = \frac{{P\bar V - RT}} {P}$

We can obtain values for $\Phi$ experimentally easily by measuring $V$, $T$ and $P$.

From the expression above we have

$\bar V = \frac{{RT}} {P} + \Phi$

(It is more obvious here that $\Phi$ is the "extra" molar volume of a non-ideal gas.) We can then write

$\int_{\mu ^\circ }^\mu {d\mu } = \int_{P^\circ }^P {\bar VdP} = \int_{P^\circ }^P {\frac{{RT}} {P}dP} + \int_{P^\circ }^P {\Phi dP}$

Where

$\mu = \mu ^\circ + RT\ln \frac{P} {{P^\circ }} + \int_{P^\circ }^P {\Phi dP}$

Since the expression for an ideal gas was chosen to be $\mu = \mu ^\circ + RT\ln \frac{f} {{f^\circ }}$,we must have

$\mu ^\circ + RT\ln \frac{f} {{f^\circ }} = \mu ^\circ + RT\ln \frac{P} {{P^\circ }} + \int_{P^\circ }^P {\Phi dP}$
$\Rightarrow RT\ln \frac{f} {{f^\circ }} - RT\ln \frac{P} {{P^\circ }} = \int_{P^\circ }^P {\Phi dP}$
$RT\ln \frac{{fP^\circ }} {{Pf^\circ }} = \int_{P^\circ }^P {\Phi dP}$

Suppose we choose $P^\circ \to 0$. Since $\mathop {\lim }_{P^\circ \to 0} f^\circ = P^\circ$, we obtain

$RT\ln \frac{f} {P} = \int_0^P {\Phi dP}$

The fugacity coefficient is defined as $\phi$ = f/P (note that for an ideal gas, $\phi$ = 1.0), and it will then verify

$\ln \phi = \frac{1} {{RT}}\int_0^P {\Phi dP}$

The integral can be evaluated via graphical integration if we experimentally measure values for $\Phi$ while varying $P$.

We can then find the fugacity coefficient of a gas at a given pressure $P$ and calculate

$f = \phi P\,$

The reference state for the expression of a real gas’ chemical potential is taken to be "ideal gas, at $P$ = 1 bar and temperature $T$". Since in the reference state the gas is considered to be ideal (it is an hypothetical reference state), we can write that for the real gas

$\mu = \mu ^\circ + RT\ln \frac{f} {{P^\circ }}$

## Fugacity of a pure liquid

Fugacity vs. pressure of ethane at −60 °F (−51 °C). Note the "breakpoint" at the saturation pressure and the curvature at higher pressures as the Poynting correction factor comes into play

For a pure fluid in vapor–liquid equilibrium, the vapor phase fugacity is equal to the liquid phase fugacity. At pressures above the saturation pressure, the liquid phase fugacity is:[4]

$f^{\rm liq}(T, P)=\phi^{\rm sat}P^{\rm sat}{\rm exp}\left[\int_{P^{\rm sat}}^P{v_{\rm liq} \over RT}dP\right]$

where $v_{\rm liq}$ is the molar volume of the liquid.

The fugacity correction factor for the vapor, $\phi^{\rm sat}$, should be evaluated at the saturation pressure and is unity when $P^{\rm sat}$ is low. The exponential term represents the Poynting correction factor and is usually near 1.0 unless pressures are very high. Frequently, the fugacity of the pure liquid is used as a reference state when defining and using mixture activity coefficients.