Hartford Township, Licking County, Ohio

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Hartford Township, Ohio
Township
Location in Licking County
Location in Licking County
Coordinates: 40°14′10″N 82°42′0″W / 40.23611°N 82.70000°W / 40.23611; -82.70000Coordinates: 40°14′10″N 82°42′0″W / 40.23611°N 82.70000°W / 40.23611; -82.70000
Country United States
State Ohio
County Licking
Area
 • Total 28.1 sq mi (72.7 km2)
 • Land 28.1 sq mi (72.7 km2)
 • Water 0.0 sq mi (0.0 km2)
Elevation[1] 1,168 ft (356 m)
Population (2000)
 • Total 1,290
 • Density 45.9/sq mi (17.7/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 39-34188[2]
GNIS feature ID 1086462[1]

Hartford Township is one of the twenty-five townships of Licking County, Ohio, United States. The 2000 census found 1,290 people in the township, 878 of whom lived in the unincorporated portions of the township.[3]

Geography[edit]

Located in the northwestern corner of the county, it borders the following townships:

The village of Hartford is located in the center of the township.

Name and history[edit]

Statewide, the only other Hartford Township is located in Trumbull County.

Government[edit]

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[4] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.

References[edit]

External links[edit]