Kersey, Indiana
From Wikipedia, the free encyclopedia
| Kersey | |
|---|---|
| — Town — | |
 Kersey
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| Coordinates: 41°11′39″N 87°09′23″W / 41.19417°N 87.15639°WCoordinates: 41°11′39″N 87°09′23″W / 41.19417°N 87.15639°W | |
| Country | United States |
| State | Indiana |
| County | Jasper |
| Township | Wheatfield |
| Elevation | 663 ft (202 m) |
| ZIP code | 46310 |
| FIPS code | 18-39600[1] |
| GNIS feature ID | 450440[2] |
Kersey is an unincorporated town in Wheatfield Township, Jasper County, Indiana.
[edit] Geography
Kersey is located at 41°11′39″N 87°09′23″W / 41.19417°N 87.15639°W.
[edit] References
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
- ^ "Kersey, Indiana". Geographic Names Information System, U.S. Geological Survey. http://geonames.usgs.gov/pls/gnispublic/f?p=gnispq:3:::NO::P3_FID:450440. Retrieved 2009-10-17.
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