Leskov Island

From Wikipedia, the free encyclopedia
Jump to: navigation, search
For Leskov Island on the coast of Antarctica, see Leskov Island (Antarctica).
Leskov Island
South sandwich islands.png
South Sandwich Islands
Zavodovski-Location.JPG
Location of Leskov Island
Geography
Coordinates 56°40′S 28°10′W / 56.667°S 28.167°W / -56.667; -28.167Coordinates: 56°40′S 28°10′W / 56.667°S 28.167°W / -56.667; -28.167
Length 1.5 km (0.93 mi)
Country
United Kingdom
Demographics
Population Uninhabited

Leskov Island is a small uninhabited island in the Traversay Islands group of the South Sandwich Islands. It is less than 1 nautical mile (2 km) long, and lies 30 nautical miles (56 km) west of Visokoi Island. It was discovered in 1819 by a Russian expedition under Fabian Gottlieb von Bellingshausen, who named it for the third lieutenant on the expedition ship Vostok.[1]

Leskov is located to the west of the main island arc of the South Sandwich Islands, and is composed of andesitic rather than basaltic lava with its highest peak reaching 190 metres (620 ft). The subduction zone forming the South Sandwich Trench lies to the east of the island arc.[2][3][4]

See also[edit]

References[edit]

  1. ^ "Leskov Island". Geographic Names Information System, U.S. Geological Survey. Retrieved 2013-06-11. 
  2. ^ Volcano World
  3. ^ LeMasurier, W. E.; Thomson, J. W., eds. (1990), Volcanoes of the Antarctic Plate and Southern Oceans, American Geophysical Union, ISBN 0-87590-172-7 
  4. ^ Global Volcanism Program

 This article incorporates public domain material from the United States Geological Survey document "Leskov Island" (content from the Geographic Names Information System).