Lind Township, Roseau County, Minnesota
|Lind Township, Minnesota|
|• Total||36.1 sq mi (93.6 km2)|
|• Land||36.1 sq mi (93.6 km2)|
|• Water||0.0 sq mi (0.0 km2)|
|Elevation||1,083 ft (330 m)|
|• Density||1.6/sq mi (0.6/km2)|
|Time zone||Central (CST) (UTC-6)|
|• Summer (DST)||CDT (UTC-5)|
|GNIS feature ID||0664787|
According to the United States Census Bureau, the township has a total area of 36.1 square miles (93.6 km²), all of it land.
As of the census of 2000, there were 58 people, 22 households, and 17 families residing in the township. The population density was 1.6 people per square mile (0.6/km²). There were 30 housing units at an average density of 0.8/sq mi (0.3/km²). The racial makeup of the township was 100.00% White.
There were 22 households out of which 31.8% had children under the age of 18 living with them, 81.8% were married couples living together, and 18.2% were non-families. 18.2% of all households were made up of individuals and 9.1% had someone living alone who was 65 years of age or older. The average household size was 2.64 and the average family size was 3.00.
In the township the population was spread out with 29.3% under the age of 18, 3.4% from 18 to 24, 24.1% from 25 to 44, 22.4% from 45 to 64, and 20.7% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 95.2 males.
The median income for a household in the township was $26,250, and the median income for a family was $33,750. Males had a median income of $8,438 versus $30,625 for females. The per capita income for the township was $11,005. None of the population and none of the families were below the poverty line.