# Magnetic moment

(Redirected from Magnetic torque)

The magnetic moment of a magnet is a quantity that determines the force that the magnet can exert on electric currents and the torque that a magnetic field will exert on it. A loop of electric current, a bar magnet, an electron, a molecule, and a planet all have magnetic moments.

Both the magnetic moment and magnetic field may be considered to be vectors having a magnitude and direction. The direction of the magnetic moment points from the south to north pole of a magnet. The magnetic field produced by a magnet is proportional to its magnetic moment as well. More precisely, the term magnetic moment normally refers to a system's magnetic dipole moment, which produces the first term in the multipole expansion of a general magnetic field. The dipole component of an object's magnetic field is symmetric about the direction of its magnetic dipole moment, and decreases as the inverse cube of the distance from the object.

## Two definitions of moment

The preferred definition of a magnetic moment has changed over time. Before the 1930s, textbooks defined the moment using magnetic poles. Since then, most have defined it in terms of Ampèrian currents.[1]

### Magnetic pole definition

An electrostatic analogue for a magnetic moment: two opposing charges separated by a finite distance.

The sources of magnetic moments in materials can be represented by poles in analogy to electrostatics. Consider a bar magnet which has magnetic poles of equal magnitude but opposite polarity. Each pole is the source of magnetic force which weakens with distance. Since magnetic poles always come in pairs, their forces partially cancel each other because while one pole pulls, the other repels. This cancellation is greatest when the poles are close to each other i.e. when the bar magnet is short. The magnetic force produced by a bar magnet, at a given point in space, therefore depends on two factors: the strength p of its poles (the magnetic pole strength), and the vector separating them. The moment is defined as[1]

$\mathbf{m}=p\boldsymbol{\ell}.$

It points in the direction from South to North pole. The analogy with electric dipoles should not be taken too far because magnetic dipoles are associated with angular momentum (see Magnetic moment and angular momentum). Nevertheless, magnetic poles are very useful for magnetostatic calculations, particularly in applications to ferromagnets.[1] Practitioners using the magnetic pole approach generally represent the magnetic field by the irrotational field H, in analogy to the electric field E.

### Current loop definition

Moment μ of a planar current having magnitude I and enclosing an area S

Suppose a planar closed loop carries an electric current I and has vector area S (x, y, and z coordinates of this vector are the areas of projections of the loop onto the yz, zx, and xy planes). Its magnetic moment μ, vector, is defined as:

$\mathbf{\mu}=I \mathbf{S}.$

By convention, the direction of the vector area is given by the right hand grip rule (curling the fingers of one's right hand in the direction of the current around the loop, when the palm of the hand is "touching" the loop's outer edge, and the straight thumb indicates the direction of the vector area and thus of the magnetic moment). [2]

If the loop is not planar, the moment is given as

$\mathbf{\mu}=\frac{I}{2}\int\mathbf{r}\times{\rm d}\mathbf{r}.$

where × is the vector cross product. In the most general case of an arbitrary current distribution in space, the magnetic moment of such a distribution can be found from the following equation:

$\mathbf{\mu}=\frac{1}{2}\int\mathbf{r}\times\mathbf{J}\,{\rm d}V,$

where r is the position vector pointing from the origin to the location of the volume element, and J is the current density vector at that location.

The above equation can be used for calculating a magnetic moment of any assembly of moving charges, such as a spinning charged solid, by substituting

$\mathbf{J}=\rho \mathbf{v},$

where ρ is the electric charge density at a given point and v is the instantaneous linear velocity of that point.

For example, the magnetic moment produced by an electric charge moving along a circular path is

$\mathbf{\mu}=\frac{1}{2}\, q\, \mathbf{r}\times\mathbf{v}$,

where r is the position of the charge q relative to the center of the circle and v is the instantaneous velocity of the charge.

Practitioners using the current loop model generally represent the magnetic field by the solenoidal field B, analogous to the electrostatic field D.

#### Magnetic moment of a solenoid

Image of a solenoid

A generalization of the above current loop is a coil, or solenoid. Its moment is the vector sum of the moments of individual turns. If the solenoid has N identical turns (single-layer winding) and vector area S,

$\mathbf{\mu}=N I \mathbf{S}.$

## Units

The unit for magnetic moment is not a base unit in the International System of Units (SI) and it can be represented in more than one way. For example, in the current loop definition, the area is measured in square meters and I is measured in amperes, so the magnetic moment is measured in ampere–square meters (A m2). In the equation for torque on a moment, the torque is measured in joules and the magnetic field in teslas, so the moment is measured in joules per tesla (J⋅T−1). These two representations are equivalent:

1 A·m2 = 1 J·T−1.

In the CGS system, there are several different sets of electromagnetism units, of which the main ones are ESU, Gaussian, and EMU. Among these, there are two alternative (non-equivalent) units of magnetic dipole moment in CGS:

(ESU CGS) 1 stat A·cm2 = 3.33564095×10−14 (A·m2 or J·T−1)

and (more frequently used)

(EMU CGS and Gaussian-CGS) 1 erg/G = 1 abA·cm2 = 10−3 (m2·A or J/T).

The ratio of these two non-equivalent CGS units (EMU/ESU) is equal exactly to the speed of light in free space, expressed in cm·s−1.

All formulas in this article are correct in SI units, but in other unit systems, the formulas may need to be changed. For example, in SI units, a loop of current with current I and area A has magnetic moment I×A (see below), but in Gaussian units the magnetic moment is I×A/c.

## Magnetic moment and angular momentum

The magnetic moment has a close connection with angular momentum called the gyromagnetic effect. This effect is expressed on a macroscopic scale in the Einstein-de Haas effect, or "rotation by magnetization," and its inverse, the Barnett effect, or "magnetization by rotation."[3] In particular, when a magnetic moment is subject to a torque in a magnetic field that tends to align it with the applied magnetic field, the moment precesses (rotates about the axis of the applied field). This is a consequence of the angular momentum associated with the moment.

Viewing a magnetic dipole as a rotating charged sphere brings out the close connection between magnetic moment and angular momentum. Both the magnetic moment and the angular momentum increase with the rate of rotation of the sphere. The ratio of the two is called the gyromagnetic ratio, usually denoted by the symbol γ.[4] [5]

For a spinning charged solid with a uniform charge density to mass density ratio, the gyromagnetic ratio is equal to half the charge-to-mass ratio. This implies that a more massive assembly of charges spinning with the same angular momentum will have a proportionately weaker magnetic moment, compared to its lighter counterpart. Even though atomic particles cannot be accurately described as spinning charge distributions of uniform charge-to-mass ratio, this general trend can be observed in the atomic world, where the intrinsic angular momentum (spin) of each type of particle is a constant: a small half-integer times the reduced Planck constant ħ. This is the basis for defining the magnetic moment units of Bohr magneton (assuming charge-to-mass ratio of the electron) and nuclear magneton (assuming charge-to-mass ratio of the proton).

## Effects of an external magnetic field on a magnetic moment

### Force on a moment

A magnetic moment in an externally-produced magnetic field has a potential energy U:

$U=-\mathbf{m}\cdot\mathbf{B}$

In a case when the external magnetic field is non-uniform, there will be a force, proportional to the magnetic field gradient, acting on the magnetic moment itself. There has been some discussion on how to calculate the force acting on a magnetic dipole. There are two expressions for the force acting on a magnetic dipole, depending on whether the model used for the dipole is a current loop or two monopoles (analogous to the electric dipole).[6] The force obtained in the case of a current loop model is

$\mathbf{F}_\text{loop}=\nabla \left(\mathbf{m}\cdot\mathbf{B}\right)$

In the case of a pair of monopoles being used (i.e. electric dipole model)

$\mathbf{F}_\text{dipole}=\left(\mathbf{m}\cdot \nabla \right) \mathbf{B}$

and one can be put in terms of the other via the relation

$\mathbf{F}_\text{loop}=\mathbf{F}_\text{dipole} + \mathbf{m}\times \left(\nabla \times \mathbf{B} \right)$

In all these expressions m is the dipole and B is the magnetic field at its position. Note that if there are no currents or time-varying electrical fields ∇ × B = 0 and the two expressions agree.

An electron, nucleus, or atom placed in a uniform magnetic field will precess with a frequency known as the Larmor frequency. See Resonance.

### Torque on a moment

The magnetic moment can also be defined as a vector relating the aligning torque on the object from an externally applied magnetic field to the field vector itself. The relationship is given by [3]

$\boldsymbol{\tau} = \mathbf{m} \times\mathbf{B}$

where τ is the torque acting on the dipole and B is the external magnetic field.

## Magnetic dipoles

A magnetic dipole is the limit of either a current loop or a pair of poles as the dimensions of the source are reduced to zero while keeping the moment constant. As long as these limits only applies to fields far from the sources, they are equivalent. However, the two models give different predictions for the internal field (see below).

### External magnetic field produced by a magnetic dipole moment

Magnetic field lines around a "magnetostatic dipole" the magnetic dipole itself is in the center and is seen from the side.

Any system possessing a net magnetic dipole moment m will produce a dipolar magnetic field (described below) in the space surrounding the system. While the net magnetic field produced by the system can also have higher-order multipole components, those will drop off with distance more rapidly, so that only the dipolar component will dominate the magnetic field of the system at distances far away from it.

The vector potential of magnetic field produced by magnetic moment m is

${\mathbf{A}}({\mathbf{r}})=\frac{\mu_{0}}{4\pi}\frac{{\mathbf{m}}\times{\mathbf{r}}}{r^{3}},$
$\mathbf{B}({\mathbf{r}})=\nabla\times{\mathbf{A}}=\frac{\mu_{0}}{4\pi}\left(\frac{3\mathbf{r}(\mathbf{m}\cdot\mathbf{r})}{r^{5}}-\frac{{\mathbf{m}}}{r^{3}}\right).$

Alternatively one can obtain the scalar potential first from the magnetic pole perspective,

$\psi({\mathbf{r}})=\frac{{\mathbf{m}}\cdot{\mathbf{r}}}{4\pi r^{3}},$

and hence magnetic field strength is

${\mathbf{H}}({\mathbf{r}})=-\nabla\psi=\frac{1}{4\pi}\left(\frac{3\mathbf{r}(\mathbf{m}\cdot\mathbf{r})}{r^{5}}-\frac{{\mathbf{m}}}{r^{3}}\right).$

The magnetic field of an ideal magnetic dipole is depicted on the left.

### Internal magnetic field of a dipole

The magnetic field of a current loop

The two models for a dipole (current loop and magnetic poles) give the same predictions for the magnetic field far from the source. However, inside the source region they give different predictions. The magnetic field between poles (see figure for Magnetic pole definition) is in the opposite direction to the magnetic moment (which points from the negative charge to the positive charge), while inside a current loop it is in the same direction (see the figure to the right). Clearly, the limits of these fields must also be different as the sources shrink to zero size. This distinction only matters if the dipole limit is used to calculate fields inside a magnetic material.[1]

If a magnetic dipole is formed by making a current loop smaller and smaller, but keeping the product of current and area constant, the limiting field is

$\mathbf{B}(\mathbf{x})=\frac{\mu_0}{4\pi}\left[\frac{3\mathbf{n}(\mathbf{n}\cdot \mathbf{m})-\mathbf{m}}{|\mathbf{x}|^3} + \frac{8\pi}{3}\mathbf{m}\delta(\mathbf{x})\right].$

Unlike the expressions in the previous section, this limit is correct for the internal field of the dipole.[1][7]

If a magnetic dipole is formed by taking a "north pole" and a "south pole", bringing them closer and closer together but keeping the product of magnetic pole-charge and distance constant, the limiting field is[1]

$\mathbf{H}(\mathbf{x}) =\frac{1}{4\pi}\left[\frac{3\mathbf{n}(\mathbf{n}\cdot \mathbf{m})-\mathbf{m}}{|\mathbf{x}|^3} - \frac{4\pi}{3}\mathbf{m}\delta(\mathbf{x})\right].$

These fields are related by $\mathbf{B}= \mu_0\left(\mathbf{H}+\mathbf{M}\right)$, where

$\mathbf{M}(\mathbf{x}) = \mathbf{m}\delta(\mathbf{x})$

is the magnetization.

### Forces between two magnetic dipoles

As discussed earlier, the force exerted by a dipole loop with moment m1 on another with moment m2 is

$\mathbf{F} =\nabla \left(\mathbf{m}_2\cdot\mathbf{B}_1\right),$

where B2 is the magnetic field due to moment 2. The result of calculating the gradient is[8][9]

$\mathbf{F}(\mathbf{r}, \mathbf{m}_1, \mathbf{m}_2) = \frac{3 \mu_0}{4 \pi r^4}\left[\mathbf{m}_2 (\mathbf{m}_1\cdot \hat{\mathbf{r}}) + \mathbf{m}_1(\mathbf{m}_2\cdot \hat{\mathbf{r}}) + \hat{\mathbf{r}}(\mathbf{m}_1\cdot\mathbf{m}_2) - 5\hat{\mathbf{r}} (\mathbf{m}_1\cdot \hat{\mathbf{r}})(\mathbf{m}_2\cdot \hat{\mathbf{r}})\right],$

where $\hat{\mathbf{r}}$ is the unit vector pointing from magnet 1 to magnet 2 and r is the distance. An equivalent expression is[9]

$\mathbf{F} = \frac {3 \mu_0} {4 \pi r^4} \left[ (\hat{\mathbf{r}} \times \mathbf{m}_1) \times \mathbf{m}_2 + (\hat{\mathbf{r}} \times \mathbf{m}_2) \times \mathbf{m}_1 - 2 \hat{\mathbf{r}}(\mathbf{m}_1 \cdot \mathbf{m}_2) + 5 \hat{\mathbf{r}} (\hat{\mathbf{r}} \times \mathbf{m}_1) \cdot (\hat{\mathbf{r}} \times \mathbf{m}_2) \right].$

The force acting on m1 is in opposite direction.

The torque of magnet 2 on magnet 1 is

$\boldsymbol{\tau}=\mathbf{m}_2 \times \mathbf{B}_1.$

## Examples of magnetic moments

### Two kinds of magnetic sources

Fundamentally, contributions to any system's magnetic moment may come from sources of two kinds: (1) motion of electric charges, such as electric currents, and (2) the intrinsic magnetism of elementary particles, such as the electron.

Contributions due to the sources of the first kind can be calculated from knowing the distribution of all the electric currents (or, alternatively, of all the electric charges and their velocities) inside the system, by using the formulas below. On the other hand, the magnitude of each elementary particle's intrinsic magnetic moment is a fixed number, often measured experimentally to a great precision. For example, any electron's magnetic moment is measured to be −9.284764×10−24 J/T.[10] The direction of the magnetic moment of any elementary particle is entirely determined by the direction of its spin (the minus in front of the value above indicates that any electron's magnetic moment is antiparallel to its spin).

The net magnetic moment of any system is a vector sum of contributions from one or both types of sources. For example, the magnetic moment of an atom of hydrogen-1 (the lightest hydrogen isotope, consisting of a proton and an electron) is a vector sum of the following contributions:

1. the intrinsic moment of the electron,
2. the orbital motion of the electron around the proton,
3. the intrinsic moment of the proton.

Similarly, the magnetic moment of a bar magnet is the sum of the intrinsic and orbital magnetic moments of the unpaired electrons of the magnet's material.

### Magnetic moment of an atom

For an atom, individual electron spins are added to get a total spin, and individual orbital angular momenta are added to get a total orbital angular momentum. These two then are added using angular momentum coupling to get a total angular momentum. The magnitude of the atomic dipole moment is then[11]

$m_\text{Atom} = g_J \mu_B \sqrt{J(J+1)}$

where J is the total angular momentum quantum number, gJ is the Landé g-factor, and μB is the Bohr magneton. The component of this magnetic moment along the direction of the magnetic field is then[12]

$m_\text{Atom}(z) = -m g_J \mu_B$

where m is called the magnetic quantum number or the equatorial quantum number, which can take on any of 2J+1 values:[13]

$-J, -(J-1) \cdots 0 \cdots +(J-1), +J$.

The negative sign occurs because electrons have negative charge.

Due to the angular momentum, the dynamics of a magnetic dipole in a magnetic field differs from that of an electric dipole in an electric field. The field does exert a torque on the magnetic dipole tending to align it with the field. However, torque is proportional to rate of change of angular momentum, so precession occurs: the direction of spin changes. This behavior is described by the Landau-Lifshitz-Gilbert equation:[14][15]

$\frac{1}{\gamma} \frac{{\rm d}\mathbf{m}}{{\rm d}t} = \mathbf{m \times H_\text{eff}} - \frac{\lambda}{\gamma m}\mathbf{m} \times \frac{{\rm d}\mathbf{m}}{{\rm d}t}$

where $\scriptstyle\gamma$ is gyromagnetic ratio, m is magnetic moment, λ is damping coefficient and Heff is effective magnetic field (the external field plus any self-field). The first term describes precession of the moment about the effective field, while the second is a damping term related to dissipation of energy caused by interaction with the surroundings.

### Magnetic moment of an electron

Electrons and many elementary particles also have intrinsic magnetic moments, an explanation of which requires a quantum mechanical treatment and relates to the intrinsic angular momentum of the particles as discussed in the article electron magnetic dipole moment. It is these intrinsic magnetic moments that give rise to the macroscopic effects of magnetism, and other phenomena, such as electron paramagnetic resonance.

The magnetic moment of the electron is

$\mathbf{m}_\text{S} = -\frac{g_\text{S} \mu_\text{B} \mathbf{S}}{\hbar},$

where μB is the Bohr magneton, S is electron spin, and the g-factor gS is 2 according to Dirac's theory, but due to quantum electrodynamic effects it is slightly larger in reality: 2.002 319 304 36. The deviation from 2 is known as the anomalous magnetic dipole moment.

Again it is important to notice that m is a negative constant multiplied by the spin, so the magnetic moment of the electron is antiparallel to the spin. This can be understood with the following classical picture: if we imagine that the spin angular momentum is created by the electron mass spinning around some axis, the electric current that this rotation creates circulates in the opposite direction, because of the negative charge of the electron; such current loops produce a magnetic moment which is antiparallel to the spin. Hence, for a positron (the anti-particle of the electron) the magnetic moment is parallel to its spin.

### Magnetic moment of a nucleus

The nuclear system is a complex physical system consisting of nucleons, i.e., protons and neutrons. The quantum mechanical properties of the nucleons include the spin among others. Since the electromagnetic moments of the nucleus depend on the spin of the individual nucleons, one can look at these properties with measurements of nuclear moments, and more specifically the nuclear magnetic dipole moment.

Most common nuclei exist in their ground state, although nuclei of some isotopes have long-lived excited states. Each energy state of a nucleus of a given isotope is characterized by a well-defined magnetic dipole moment, the magnitude of which is a fixed number, often measured experimentally to a great precision. This number is very sensitive to the individual contributions from nucleons, and a measurement or prediction of its value can reveal important information about the content of the nuclear wave function. There are several theoretical models that predict the value of the magnetic dipole moment and a number of experimental techniques aiming to carry out measurements in nuclei along the nuclear chart.

### Magnetic moment of a molecule

Any molecule has a well-defined magnitude of magnetic moment, which may depend on the molecule's energy state. Typically, the overall magnetic moment of a molecule is a combination of the following contributions, in the order of their typical strength:

#### Examples of molecular magnetism

• Oxygen molecule, O2, exhibits strong paramagnetism, due to unpaired spins of its outermost two electrons.
• Carbon dioxide molecule, CO2, mostly exhibits diamagnetism, a much weaker magnetic moment of the electron orbitals that is proportional to the external magnetic field. In the rare instance when a magnetic isotope, such as 13C or 17O, is present, it will contribute its nuclear magnetism to the molecule's magnetic moment.
• Hydrogen molecule, H2, in a weak (or zero) magnetic field exhibits nuclear magnetism, and can be in a para- or an ortho- nuclear spin configuration.

### Elementary particles

In atomic and nuclear physics, the symbol μ represents the magnitude of the magnetic moment, often measured in Bohr magnetons or nuclear magnetons, associated with the intrinsic spin of the particle and/or with the orbital motion of the particle in a system. Values of the intrinsic magnetic moments of some particles are given in the table below:

Intrinsic magnetic moments and spins of some elementary particles [16]
Particle Magnetic dipole moment in SI units (10−27 JT−1) Spin quantum number (dimensionless)
electron -9284.764 1/2
proton 14.106067 1/2
neutron -9.66236 1/2
muon -44.904478 1/2
deuteron 4.3307346 1
triton 15.046094 1/2
helion -10.746174 1/2
alpha particle 0 0

For relation between the notions of magnetic moment and magnetization see magnetization.

## References and notes

1. Brown, Jr. 1962
2. ^
3. ^ a b B. D. Cullity, C. D. Graham (2008). Introduction to Magnetic Materials (2 ed.). Wiley-IEEE Press. p. 103. ISBN 0-471-47741-9.
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5. ^ Richard B. Buxton (2002). Introduction to functional magnetic resonance imaging. Cambridge University Press. p. 136. ISBN 0-521-58113-3.
6. ^ Boyer, Timothy H. (1988). "The Force on a Magnetic Dipole". American Journal of Physics 56 (8): 688–692. Bibcode:1988AmJPh..56..688B. doi:10.1119/1.15501.
7. ^ Jackson 1975, p. 184
8. ^ Furlani, Edward P. (2001). Permanent Magnet and Electromechanical Devices: Materials, Analysis, and Applications. Academic Press. p. 140. ISBN 0-12-269951-3.
9. ^ a b K.W. Yung, P.B. Landecker, D.D. Villani (1998). An Analytic Solution for the Force between Two Magnetic Dipoles (PDF). Retrieved November 24, 2012.
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11. ^ RJD Tilley (2004). Understanding Solids. John Wiley and Sons. p. 368. ISBN 0-470-85275-5.
12. ^ Paul Allen Tipler, Ralph A. Llewellyn (2002). Modern Physics (4 ed.). Macmillan. p. 310. ISBN 0-7167-4345-0.
13. ^ JA Crowther (2007). Ions, Electrons and Ionizing Radiations (reprinted Cambridge (1934) 6 ed.). Rene Press. p. 277. ISBN 1-4067-2039-9.
14. ^ Stuart Alan Rice (2004). Advances in chemical physics. Wiley. pp. 208 ff. ISBN 0-471-44528-2.
15. ^ Marcus Steiner (2004). Micromagnetism and Electrical Resistance of Ferromagnetic Electrodes for Spin Injection Devices. Cuvillier Verlag. p. 6. ISBN 3-86537-176-0.
16. ^ "Search results matching ' magnetic moment '...". CODATA internationally recommended values of the Fundamental Physical Constants. National Institute of Standards and Technology. Retrieved 11 May 2012.