Maxwell–Boltzmann distribution

Maxwell–Boltzmann
	Probability density function;
	Cumulative distribution function;
parameters:
support:
pdf:
cdf:	where erf is the Error function
mean:
median:
mode:
variance:
skewness:
kurtosis:
entropy:
mgf:
cf:

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The Maxwell–Boltzmann distribution describes particle speeds in gases, where the particles do not constantly interact with each other but move freely between short collisions. It describes the probability of a particle's speed (the magnitude of its velocity vector) being near a given value as a function of the temperature of the system, the mass of the particle, and that speed value. This probability distribution is named after James Clerk Maxwell and Ludwig Boltzmann.

[edit] Physical applications of the Maxwell–Boltzmann distribution

The Maxwell–Boltzmann distribution applies to ideal gases close to thermodynamic equilibrium, negligible quantum effects, and non-relativistic speeds. It forms the basis of the kinetic theory of gases, which explains many fundamental gas properties, including pressure and diffusion. The Maxwell–Boltzmann distribution is usually thought of as the distribution for molecular speeds, but it can also refer to the distribution for velocities, momenta, and magnitude of the momenta of the molecules, each of which will have a different probability distribution function, all of which are related

[edit] Derivation

The original derivation by Maxwell assumed all three directions would behave in the same fashion, but a later derivation by Boltzmann dropped this assumption using kinetic theory. The Maxwell–Boltzmann distribution can now most readily be derived from the Boltzmann distribution for energies (see also the Maxwell–Boltzmann statistics of statistical mechanics):

$\frac{N_i}{N} = \frac{g_i \exp\left(-E_i/kT \right) } { \sum_{j}^{} g_j \,{\exp\left(-E_j/kT\right)} } \qquad\qquad (1)$

where N_i is the number of molecules at equilibrium temperature T, in a state i which has energy E_i and degeneracy g_i, N is the total number of molecules in the system and k is the Boltzmann constant. (Note that sometimes the above equation is written without the degeneracy factor g_i. In this case the index i will specify an individual state, rather than a set of g_i states having the same energy E_i.) Because velocity and speed are related to energy, Equation 1 can be used to derive relationships between temperature and the speeds of molecules in a gas. The denominator in this equation is known as the canonical partition function.

[edit] Distribution for the momentum vector

What follows is a derivation wildly different from the derivation described by James Clerk Maxwell and later described with fewer assumptions by Ludwig Boltzmann. Instead it is close to Boltzmann's later approach of 1877.

For the case of an "ideal gas" consisting of non-interacting atoms in the ground state, all energy is in the form of kinetic energy. The relationship between kinetic energy and momentum for massive particles is

$E=\frac{p^2}{2m} \qquad\qquad (2)$

where p² is the square of the momentum vector p = [p_x, p_y, p_z]. We may therefore rewrite Equation 1 as:

$\frac{N_i}{N} = \frac{1}{Z} \exp \left[ -\frac{p_x^2 + p_y^2 + p_z^2}{2mkT} \right] \qquad\qquad (3)$

where Z is the partition function, corresponding to the denominator in Equation 1. Here m is the molecular mass of the gas, T is the thermodynamic temperature and k is the Boltzmann constant. This distribution of N_i/N is proportional to the probability density function f_p for finding a molecule with these values of momentum components, so:

$f_\mathbf{p} (p_x, p_y, p_z) = \frac{c}{Z} \exp \left[ -\frac{p_x^2 + p_y^2 + p_z^2}{2mkT} \right]. \qquad\qquad (4)$

The normalizing constant c, can be determined by recognizing that the probability of a molecule having any momentum must be 1. Therefore the integral of equation 4 over all p_x, p_y, and p_z must be 1.

It can be shown that:

$c = \frac{Z}{(2 \pi mkT)^{3/2}}. \qquad\qquad (5)$

Substituting Equation 5 into Equation 4 gives:

$f_\mathbf{p} (p_x, p_y, p_z) = \left( \frac{1}{2 \pi mkT} \right)^{3/2} \exp \left[ -\frac{p_x^2 + p_y^2 + p_z^2}{2mkT} \right]. \qquad\qquad (6)$

The distribution is seen to be the product of three independent normally distributed variables $p x$ , $p y$ , and $p z$ , with variance $m k T$ . Additionally, it can be seen that the magnitude of momentum will be distributed as a Maxwell–Boltzmann distribution, with $a=\sqrt{mkT}$ . The Maxwell-Boltzmann distribution for the momentum (or equally for the velocities) can be obtained more fundamentally using the H-theorem at equilibrium within the kinetic theory framework.

[edit] Distribution for the energy

Using p² = 2mE, and the distribution function for the magnitude of the momentum (see below), we get the energy distribution:

$f_E\,dE=f_p\left(\frac{dp}{dE}\right)\,dE =2\sqrt{\frac{E}{\pi(kT)^3}}~\exp\left[\frac{-E}{kT}\right]\,dE. \qquad \qquad(7)$

Since the energy is proportional to the sum of the squares of the three normally distributed momentum components, this distribution is a chi-square distribution with three degrees of freedom:

$f_E(E)\,dE=\chi^2(x;3)\,dx$

where

$x=\frac{2E}{kT}.\,$

The Maxwell–Boltzmann distribution can also be obtained by considering the gas to be a quantum gas.

[edit] Distribution for the velocity vector

Recognizing that the velocity probability density f_v is proportional to the momentum probability density function by

$f_\mathbf{v} d^3v = f_\mathbf{p} \left(\frac{dp}{dv}\right)^3 d^3v$

and using p = mv we get

$f_\mathbf{v} (v_x, v_y, v_z) = \left(\frac{m}{2 \pi kT} \right)^{3/2} \exp \left[- \frac{m(v_x^2 + v_y^2 + v_z^2)}{2kT} \right], \qquad\qquad$

which is the Maxwell–Boltzmann velocity distribution. The probability of finding a particle with velocity in the infinitesimal element [dv_x, dv_y, dv_z] about velocity v = [v_x, v_y, v_z] is

$f_\mathbf{v} \left(v_x, v_y, v_z\right)\, dv_x\, dv_y\, dv_z.$

Like the momentum, this distribution is seen to be the product of three independent normally distributed variables $v x$ , $v y$ , and $v z$ , but with variance $\frac{kT}{m}$ . It can also be seen that the Maxwell–Boltzmann velocity distribution for the vector velocity [v_x, v_y, v_z] is the product of the distributions for each of the three directions:

$f_v \left(v_x, v_y, v_z\right) = f_v (v_x)f_v (v_y)f_v (v_z)$

where the distribution for a single direction is

$f_v (v_i) = \sqrt{\frac{m}{2 \pi kT}} \exp \left[ \frac{-mv_i^2}{2kT} \right]. \qquad\qquad$

This distribution has the form of a normal distribution, with variance $\frac{kT}{m}$ . As expected for a gas at rest, the average velocity in any particular direction is zero.

[edit] Distribution for the speed

The speed probability density functions of the speeds of a few noble gases at a temperature of 298.15 K (25 °C). The y-axis is in s/m so that the area under any section of the curve (which represents the probability of the speed being in that range) is dimensionless.

Usually, we are more interested in the speeds of molecules rather than their component velocities. The Maxwell-Boltzmann distribution for the speed is written as

$f (v) = 4 \pi \left(\frac{m}{2 \pi kT}\right)^{3/2}\!\!v^2 \exp \left[ \frac{-mv^2}{2kT} \right] \qquad$

where speed, v, is defined as

$v = \sqrt{v_x^2 + v_y^2 + v_z^2}$

Note that the units of f(v) in equation are probability per speed, or just reciprocal speed as in the graph at the right.

Since the speed is the square root of the sum of squares of the three independent, normally distributed velocity components, this distribution is a Maxwell–Boltzmann distribution, with $a=\sqrt{kT/m}$ .

We are often more interested in quantities such as the average speed of the particles rather than the actual distribution. The mean speed, most probable speed (mode), and root-mean-square can be obtained from properties of the Maxwell–Boltzmann distribution.

[edit] Distribution for relative speed

Relative speed is defined as $u = {v \over v_p}$ , where $v_p = \sqrt { \frac{2kT}{m} } = \sqrt { \frac{2RT}{M} }$ is the most probable speed (see the next section).

[edit] Typical speeds

Although the above equation gives the distribution for the speed or, in other words, the fraction of time the molecule has a particular speed, we are often more interested in quantities such as the average speed rather than the whole distribution.

The most probable speed, v_p, is the speed most likely to be possessed by any molecule (of the same mass m) in the system and corresponds to the maximum value or mode of f(v). To find it, we calculate df/dv, set it to zero and solve for v:

$\frac{df(v)}{dv} = 0$

which yields:

$v_p = \sqrt { \frac{2kT}{m} } = \sqrt { \frac{2RT}{M} }$

Where R is the gas constant and M = N_A m is the molar mass of the substance.

For nitrogen (the primary component of air) at room temperature (300 K), this gives $v p = 600$ m/s

The mean speed is the mathematical average of the speed distribution

$\langle v \rangle = \int_0^{\infin} v \, f(v) \, dv= \sqrt { \frac{8kT}{\pi m}}= \sqrt { \frac{8RT}{\pi M}}$

The root mean square speed, v_rms is the square root of the average squared speed:

$v_\mathrm{rms} = \left(\int_0^{\infin} v^2 \, f(v) \, dv \right)^{1/2}= \sqrt { \frac{3kT}{m}}= \sqrt { \frac{3RT}{M} }$

The typical speeds are related as follows:

$v_p < \langle v \rangle < v_\mathrm{rms}.$

[edit] Distribution for relativistic speeds

Maxwell-Juttner speed distribution (relativistic Maxwellian) for electron gas at different temperatures

As the gas becomes hotter and kT approaches or exceeds mc², the probability distribution for the speed in this relativistic Maxwellian gas is given by the Maxwell-Juttner distribution^[1]:

$f(\gamma) = \frac {\gamma^2 \beta }{\theta K_2(1/\theta)} \mathrm{exp} \left( - \frac {\gamma}{\theta} \right) \qquad (11)$

where $\beta = \frac {v}{c},$ $\gamma=\frac{1}{\sqrt { 1-{\beta^2} }},$ $\theta=\frac{kT}{mc^2},$ and $K 2$ is the modified Bessel function of the second kind.

[edit] See also

[edit] References

^ Synge, J.L., The relativistic gas, Noord-Holland, 1957

[edit] External links

"The Maxwell Speed Distribution" from The Wolfram Demonstrations Project at Mathworld

[Synge-0] Synge, J.L., The relativistic gas, Noord-Holland, 1957

[1]

Maxwell–Boltzmann distribution

From Wikipedia, the free encyclopedia

Contents

[edit] Physical applications of the Maxwell–Boltzmann distribution

[edit] Derivation

[edit] Distribution for the momentum vector

[edit] Distribution for the energy

[edit] Distribution for the velocity vector

[edit] Distribution for the speed

[edit] Distribution for relative speed

[edit] Typical speeds

[edit] Distribution for relativistic speeds

[edit] See also

[edit] References

[edit] External links

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Probability density function
Cumulative distribution function
parameters:	$a>0\,$
support:	$x\in [0;\infty)$
pdf:	$\sqrt{\frac{2}{\pi}} \frac{x^2 e^{-x^2/(2a^2)}}{a^3}$
cdf:	$\textrm{erf}\left(\frac{x}{\sqrt{2} a}\right) -\sqrt{\frac{2}{\pi}} \frac{x e^{-x^2/(2a^2)}}{a}$ where erf is the Error function
mean:	$\mu=2a \sqrt{\frac{2}{\pi}}$
median:
mode:	$\sqrt{2} a$
variance:	$\sigma^2=\frac{a^2(3 \pi - 8)}{\pi}$
skewness:	$\gamma_1=\frac{2 \sqrt{2} (5 \pi - 16)}{(3 \pi - 8)^{3/2}}$
kurtosis:	$\gamma_2=-4\frac{96-40\pi+3\pi^2}{(3 \pi - 8)^2}$
entropy:
mgf:
cf: