It is also called molarity, amount-of-substance concentration, amount concentration, substance concentration, or simply concentration. The volume in the definition refers to the volume of the solution, not the volume of the solvent. One litre of a solution usually contains either slightly more or slightly less than 1 litre of solvent because the process of dissolution causes volume of liquid to increase or decrease.
- 1 mol/L = 1 mol/dm3 = 1 mol dm−3 = 1 M = 1000 mol/m3.
An SI prefix is often used to denote concentrations. Commonly used units are listed in the table hereafter:
|Name||Abbreviation||Concentration||Concentration (SI unit)|
|millimolar||mM||10−3 mol/dm3||100 mol/m3|
|micromolar||μM||10−6 mol/dm3||10−3 mol/m3|
|nanomolar||nM||10−9 mol/dm3||10−6 mol/m3|
|picomolar||pM||10−12 mol/dm3||10−9 mol/m3|
|femtomolar||fM||10−15 mol/dm3||10−12 mol/m3|
|attomolar||aM||10−18 mol/dm3||10−15 mol/m3|
|zeptomolar||zM||10−21 mol/dm3||10−18 mol/m3|
(1 particle per 1.6 L)
Related quantities 
Number concentration 
The conversion to number concentration is given by:
Mass concentration 
The conversion to mass concentration is given by:
where is the molar mass of constituent .
Mole fraction 
The conversion to mole fraction is given by:
where is the average molar mass of the solution and is the density of the solution.
Mass fraction 
The conversion to mass fraction is given by:
The conversion to molality (for binary mixtures) is:
where the solute is assigned the subscript 2.
For solutions with more than one solute, the conversion is:
Sum of molar concentrations - normalizing relation 
The sum of molar concentrations gives the total molar concentration, namely the density of the mixture divided by the molar mass of the mixture or by another name the reciprocal of the molar volume of the mixture.
Sum of products molar concentrations-partial molar volumes 
The sum of products between these quantities equals one.
Dependence on volume 
Molar concentration depends on the variation of the volume of the solution due mainly to thermal expansion.
Spatial variation and diffusion 
Molar and mass concentration have different values in space where diffusion happens.
Example 1: Consider 11.6 g of NaCl dissolved in 100 g of water. The final mass concentration (NaCl) will be:
- (NaCl) = 11.6 g / (11.6 g + 100 g) = 0.104 g/g = 10.4 %
The density of such a solution is 1.07 g/mL, thus its volume will be:
- = (11.6 g + 100 g) / (1.07 g/mL) = 104.3 mL
The molar concentration of NaCl in the solution is therefore:
- (NaCl) = (11.6 g / 58 g/mol) / 104.3 mL = 0.00192 mol/mL = 1.92 mol/L
Here, 58 g/mol is the molar mass of NaCl.
Example 2: Another typical task in chemistry is the preparation of 100 mL (= 0.1 L) of a 2 mol/L solution of NaCl in water. The mass of salt needed is:
- (NaCl) = 2 mol/L * 0.1 L * 58 g/mol = 11.6 g
To create the solution, 11.6 g NaCl are placed in a volumetric flask, dissolved in some water, then followed by the addition of more water until the total volume reaches 100 mL.
Example 3: The density of water is approximately 1000 g/L and its molar mass is 18.02 g/mol (or 1/18.02=0.055 mol/g). Therefore, the molar concentration of water is:
- (H2O) = 1000 g/L / (18.02 g/mol) = 55.5 mol/L
Likewise, the concentration of solid hydrogen (molar mass = 2.02 g/mol) is:
- (H2) = 88 g/L / (2.02 g/mol) = 43.7 mol/L
The concentration of pure osmium tetroxide (molar mass = 254.23 g/mol) is:
- (OsO4) = 5.1 kg/L / (254.23 g/mol) = 20.1 mol/L.
- = 60 / (10−15 L)= 6×1016 L−1
The molar concentration is:
- = 6×1016 L−1 / (6×1023 mol−1) = 10−7 mol/L = 100 nmol/L
If the concentration refers to original chemical formula in solution, the molar concentration is sometimes called formal concentration. For example, if a sodium carbonate solution has a formal concentration of (Na2CO3) = 1 mol/L, the molar concentrations are (Na+) = 2 mol/L and (CO32-) = 1 mol/L because the salt dissociates into these ions.
- Molar Solution Concentration Calculator
- Experiment to determine the molar concentration of vinegar by titration