Nashville, Hancock County, Indiana
From Wikipedia, the free encyclopedia
| Nashville | |
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| — Town — | |
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| Coordinates: 39°55′42″N 85°39′34″W / 39.92833°N 85.65944°WCoordinates: 39°55′42″N 85°39′34″W / 39.92833°N 85.65944°W | |
| Country | United States |
| State | Indiana |
| County | Hancock |
| Township | Brown |
| Elevation | 938 ft (286 m) |
| ZIP code | 46186 |
| FIPS code | 18-52045[1] |
| GNIS feature ID | 439942[2] |
Nashville is an unincorporated community in Brown Township, Hancock County, Indiana.
[edit] Geography
Nashville is located at 39°55′42″N 85°39′34″W / 39.92833°N 85.65944°W.
[edit] References
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
- ^ "Nashville, Hancock County, Indiana". Geographic Names Information System, U.S. Geological Survey. http://geonames.usgs.gov/pls/gnispublic/f?p=gnispq:3:::NO::P3_FID:439942. Retrieved 2009-10-17.
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