# Rate-determining step

In chemical kinetics, the rate (or velocity) of a reaction mechanism with several steps is often determined by the slowest step, known as the rate-determining step (RDS) or rate-limiting step. The experimental rate equation can help to identify which step is rate-determining.

In a reaction coordinate, the transition state with the highest energy is the rate-determining step of a given reaction.

The concept of the rate-determining step is very important to the optimization and understanding of many chemical processes such as catalysis and combustion.

## Example reaction: NO 2 + CO

As an example, consider the gas-phase reaction NO
2
+ CO → NO + CO
2
. If this reaction occurred in a single step, its reaction rate (r) would be proportional to the rate of collisions between NO
2
and CO molecules r = k[NO
2
][CO], where k is the reaction rate constant and square brackets indicate a molar concentration.

### First step rate-determining

In fact, however, the observed reaction rate is second order in NO
2
and zero order in CO,[1] with rate equation r = k[NO
2
]2. This suggests that the rate is determined by a step in which two NO
2
molecules react, with the CO molecule entering at another, faster, step. A possible mechanism in two elementary steps which explains the rate equation is:

1. NO
2
+ NO
2
→ NO + NO
3
(slow step, rate-determining)
2. NO
3
+ CO → NO
2
+ CO
2
(fast step)

In this mechanism the reactive intermediate species NO
3
is formed in the first step with rate r1 and reacts with CO in the second step with rate r2. However NO
3
can also react with NO if the first step occurs in the reverse direction (NO + NO
3
→ 2 NO
2
) with rate r-1, where the minus sign indicates the rate of a reverse reaction.

The concentration of a reactive intermediate such as [NO
3
] remains low and almost constant. It may therefore be estimated by the steady state approximation, which specifies that the rate at which it is formed equals the (total) rate at which it is consumed. In this example NO
3
is formed in one step and reacts in two, so that $\frac{{d} {[NO_3]}} {dt}=r_1 - r_2 - r_{-1} \approx 0$

The statement that the first step is the slow step actually means that the first step in the reverse direction is slower than the second step in the forward direction, so that almost all NO
3
is consumed by reaction with CO and not with NO. That is, r-1 << r2, so that r1 – r2 ≈ 0. But the overall rate of reaction is the rate of formation of final product (here CO
2
), so that r = r2 ≈ r1. That is, the overall rate is determined by the rate of the first step, and (almost) all molecules which react by the first step continue to the second step which is just as fast.

### If the second step were rate-determining

The other possible case would be that the second step is slow and rate-determining, meaning that it is slower than the first step in the reverse direction: r2 << r-1. In this hypothesis, r1 – r-1 ≈ 0, so that the first step is (almost) at equilibrium. The overall rate is determined by the second step, r = r2 << r1, as very few molecules which react by the first step continue to the second step which is much slower. However this hypothesis can be rejected (for the example reaction) since it implies a rate equation which disagrees with experiment.

If the first step were at equilibrium, then its equilibrium constant expression permits calculation of the concentration of the intermediate NO
3
in terms of more stable (and more easily measured) reactant and product species

$K_1=\frac{{[NO]} {[NO_3]}} {{[NO_2]}^2}$
$[NO_3]=K_1\frac{{[NO_2]^2}} {{[NO]}}$

The overall reaction rate would then be

$r=r_2 = k_2[NO_3][CO] = k_2 K_1\frac{{[NO_2]^2 [CO]}} {{[NO]}}$,

which disagrees with the experimental rate law given above, and so disproves the hypothesis that the second step is rate-determining.

## Nucleophilic substitution

Another example is the unimolecular nucleophilic substitution (SN1) reaction in organic chemistry, where it is the first, rate-determining step that is unimolecular. A specific case is the basic hydrolysis of tert-butyl bromide (t-C
4
H
9
Br
) by aqueous sodium hydroxide. The mechanism has two steps (where R denotes the tert-butyl radical t-C
4
H
9
)

1. Formation of a carbocation R-Br → R+
+ Br
2. Nucleophilic attack by one water molecule R+
+ OH
→ ROH.

This reaction is found to be first-order with rate = k[RBr], which indicates that the first step is slow and determines the rate. The second step with OH- is much faster so the overall rate is independent of the concentration of OH-.

In contrast the alkaline hydrolysis of methyl bromide (CH
3
Br
) is a bimolecular nucleophilic substitution (SN2) reaction in a single bimolecular step. Its rate law is second-order, rate = k[RBr][OH
].

## Composition of the transition state

A useful rule in the determination of mechanism is that the concentration factors in the rate law indicate the composition and charge of the activated complex or transition state.[2] For the NO
2
-CO reaction above, the rate depends on [NO
2
]2 so that the activated complex has composition N
2
O
4
, with 2 NO
2
entering the reaction before the transition state and CO reacting after the transition state.

A multistep example is the reaction between oxalic acid and chlorine in aqueous solution: H
2
C
2
O
4
+ Cl
2
→ 2 CO
2
+ 2 H+
+ 2 Cl
.[2] The observed rate law is

$v = k\frac{{[Cl_2][H_2C_2O_4]}} {{[H^+]^2[Cl^-]}}$,

which implies an activated complex in which the reactants lose 2H+
+ Cl
before the rate-determining step. The formula of the activated complex is Cl
2
+ H
2
C
2
O
4
– 2 H+
Cl
+ x H
2
O
, or C
2
O
4
Cl(H
2
O)
x
(An unknown number of water molecules are added because the possible dependence of the reaction rate on H
2
O
was not studied, since the data were obtained in water solvent at a large and essentially unvarying concentration.)

One possible mechanism in which the preliminary steps are known to be rapid is[2]

Cl
2
+ H
2
O
$\rightleftharpoons$ HOCl + Cl
+ H+
H
2
C
2
O
4
$\rightleftharpoons$ H+
+ HC
2
O
4
HOCl + HC
2
O
4
H
2
O
+ Cl
+ 2 CO
2

## Diffusion control

In the previous examples the rate determining step was one of the sequential chemical reactions leading to a product. The rate-determining step can also be the transport of reactants to interact and form the product. This case is referred to as diffusion control and, in general, occurs where the formation of product from the activated complex is very rapid and thus the supply of reactants and their interaction is rate determining.