Reduction of order
Reduction of order is a technique in mathematics for solving second-order linear ordinary differential equations. It is employed when one solution y1(x) is known and a second linearly independent solution y2(x) is desired. The method also applies to n-th order equations. In this case the ansatz will yield a (n-1)-th order equation for v.
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[edit] Second-order linear ordinary differential equations
[edit] An Example
Consider the general second-order linear constant coefficient ODE
where a,b,c are real non-zero coefficients. Furthermore, assume that the associated characteristic equation
has repeated roots (i.e. the discriminant, b2 − 4ac, vanishes). Thus we have
Thus our one solution to the ODE is
To find a second solution we take as a guess
where v(x) is an unknown function to be determined. Since y2(x) must satisfy the original ODE, we substitute it back in to get
Rearranging this equation in terms of the derivatives of v(x) we get
Since we know that y1(x) is a solution to the original problem, the coefficient of the last term is equal to zero. Furthermore, substituting y1(x) into the second term's coefficient yields (for that coefficient)
Therefore we are left with
Since a is assumed non-zero and y1(x) is an exponential function and thus never equal to zero we simply have
This can be integrated twice to yield
where c1,c2 are constants of integration. We now can write our second solution as
Since the second term in y2(x) is a scalar multiple of the first solution (and thus linearly dependent) we can drop that term, yielding a final solution of
Finally, we can prove that the second solution y2(x) found via this method is linearly independent of the first solution by calculating the Wronskian
Thus y2(x) is the second linearly independent solution we were looking for.
[edit] General method
Given a linear differential equation
and a single solution (y1(t)), let the second solution be defined
where v(t) is an arbitrary function. Thus
and
If these are substituted for y, y', and y'' in the differential equation, then
Since y1(t) is a solution of the original differential equation, y1''(t) + p(t)y1'(t) + q(t)y1(t) = 0, so we can reduce to
which is a first-order differential equation for v'(t) (reduction of order). Divide by y1(t), obtaining
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Integrating factor :
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Multiplying the differential equation with the integrating factor μ(t), the equation in v(t) can be reduced to
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Once v'(t) is solved, integrate it and enter into the original equation for y2:
where
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[edit] See also
[edit] References
- W. E. Boyce and R. C. DiPrima, Elementary Differential Equations and Boundary Value Problems (8th edition), John Wiley & Sons, Inc., 2005. ISBN 0-471-43338-1.
- Teschl, Gerald. Ordinary Differential Equations and Dynamical Systems. Providence: American Mathematical Society. http://www.mat.univie.ac.at/~gerald/ftp/book-ode/.
- Eric W. Weisstein, Second-Order Ordinary Differential Equation Second Solution, From MathWorld--A Wolfram Web Resource.




















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