Romanian general election, 1928

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General elections were held in Romania in December 1928.[1] The Chamber of Deputies was elected on 12 December, whilst the Senate was elected in three stages on 15, 17 and 19 December.[1] The result was a victory for the National Peasants' Party-led alliance, which won 348 of the 387 seats in the Chamber of Deputies and 105 of the 110 seats in the Senate.[2] Of the 348 Chamber seats won by the alliance, the National Peasants' Party won 326, the Social Democratic Party won 9, the German Party won 8, the Hungarian People's Party won 2 and three were won by other parties.[2]

Results[edit]

Party Chamber Senate
Votes % Seats +/– Votes % Seats +/–
National Peasants' Party-led alliance 2,208,922 79.2 348 +294 105 +88
National Liberal Party 185,939 6.7 13 –305 0 –92
Magyar Party 172,099 6.2 16 New 3 New
National Party-People's Party 70,790 2.5 5 New 0 New
Peasant Party–Lupu 70,506 2.5 5 New 0 New
Peasant Workers Bloc 38,851 1.4 0 New 0 New
National-Christian Defense League 32,273 1.2 0 New 0 New
Other parties 8,051 0.3 0 3
Jewish Party 0 2 New
Invalid/blank votes 53,249
Total 2,840,680 100 387 0 110 –3
Registered voters/turnout 3,671,352 77.4
Source: Nohlen & Stöver

References[edit]

  1. ^ a b Nohlen, D & Stöver, P (2010) Elections in Europe: A data handbook, p1591 ISBN 978-3-8329-5609-7
  2. ^ a b Nohlen & Stöver, pp1610-1611