Roscoe Township, Winnebago County, Illinois

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Roscoe Township
Township
Location in Winnebago County
Location in Winnebago County
Coordinates: 42°26′57″N 88°59′38″W / 42.44917°N 88.99389°W / 42.44917; -88.99389Coordinates: 42°26′57″N 88°59′38″W / 42.44917°N 88.99389°W / 42.44917; -88.99389
Country United States
State Illinois
County Winnebago
Established November 6, 1849 (1849-11-06)
Government
 • Supervisor Thomas Hawes
Area
 • Total 31.27 sq mi (81.0 km2)
 • Land 30.69 sq mi (79.5 km2)
 • Water 0.58 sq mi (1.5 km2)  1.85%
Elevation 778 ft (237 m)
Population (2010)
 • Total 19,694
 • Density 641.8/sq mi (247.8/km2)
Time zone CST (UTC-6)
 • Summer (DST) CDT (UTC-5)
[1][2]

Roscoe Township is located in Winnebago County, Illinois. As of the 2010 census, its population was 19,694 and it contained 7,497 housing units.[3]

Geography[edit]

According to the 2010 census, the township has a total area of 31.27 square miles (81.0 km2), of which 30.69 square miles (79.5 km2) (or 98.15%) is land and 0.58 square miles (1.5 km2) (or 1.85%) is water.[3]

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