San Cipriano Po
From Wikipedia, the free encyclopedia
|San Cipriano Po|
|Comune di San Cipriano Po|
|Province||Province of Pavia (PV)|
|• Total||8.7 km2 (3.4 sq mi)|
|Population (Dec. 2004)|
|• Density||50/km2 (130/sq mi)|
|Time zone||CET (UTC+1)|
|• Summer (DST)||CEST (UTC+2)|
San Cipriano Po is a comune (municipality) in the Province of Pavia in the Italian region Lombardy, located about 40 km south of Milan and about 12 km southeast of Pavia. As of 31 December 2004, it had a population of 435 and an area of 8.7 km².
- All demographics and other statistics: Italian statistical institute Istat.
|This article on a location in the Province of Pavia is a stub. You can help Wikipedia by expanding it.|