Seward Township, Kosciusko County, Indiana
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| Seward Township | |
|---|---|
| — Township — | |
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| Coordinates: 41°06′29″N 85°56′46″W / 41.10806°N 85.94611°WCoordinates: 41°06′29″N 85°56′46″W / 41.10806°N 85.94611°W | |
| Country | United States |
| State | Indiana |
| County | Kosciusko |
| Government | |
| • Type | Indiana township |
| Area | |
| • Total | 36.28 sq mi (93.96 km2) |
| • Land | 35.33 sq mi (91.5 km2) |
| • Water | 0.95 sq mi (2.47 km2) |
| Elevation[1] | 879 ft (268 m) |
| Population (2000) | |
| • Total | 2,462 |
| • Density | 69.69/sq mi (26.91/km2) |
| FIPS code | 18-68796[2] |
| GNIS feature ID | 453840 |
Seward Township is one of seventeen townships in Kosciusko County, Indiana. As of the 2000 census, its population was 2,462.
[edit] References
- ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. http://geonames.usgs.gov. Retrieved 2008-01-31.
- ^ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
[edit] External links
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