Seward Township, Winnebago County, Illinois

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Seward Township
Township
Combined township building and fire station
Combined township building and fire station
Location in Winnebago County
Location in Winnebago County
Coordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°W / 42.24583; -89.33861Coordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°W / 42.24583; -89.33861
Country United States
State Illinois
County Winnebago
Established November 6, 1849 (1849-11-06)
Government
 • Supervisor Garelt S. Stahl
Area
 • Total 35.82 sq mi (92.8 km2)
 • Land 35.81 sq mi (92.7 km2)
 • Water 0 sq mi (0 km2)  0%
Elevation 853 ft (260 m)
Population (2010)
 • Total 917
 • Density 25.6/sq mi (9.9/km2)
Time zone CST (UTC-6)
 • Summer (DST) CDT (UTC-5)
[1][2]

Seward Township is located in Winnebago County, Illinois. As of the 2010 census, its population was 917 and it contained 394 housing units.[3]

Geography[edit]

According to the 2010 census, the township has a total area of 35.82 square miles (92.8 km2), all land.[3]

References[edit]

External links[edit]