St. Albans Township, Licking County, Ohio

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St. Albans Township, Ohio
Township
Location of St. Albans Township in Licking County
Location of St. Albans Township in Licking County
Coordinates: 40°5′34″N 82°37′26″W / 40.09278°N 82.62389°W / 40.09278; -82.62389Coordinates: 40°5′34″N 82°37′26″W / 40.09278°N 82.62389°W / 40.09278; -82.62389
Country United States
State Ohio
County Licking
Area
 • Total 26.7 sq mi (69.1 km2)
 • Land 26.7 sq mi (69.1 km2)
 • Water 0.0 sq mi (0.0 km2)
Elevation[1] 1,050 ft (320 m)
Population (2000)
 • Total 2,060
 • Density 77.2/sq mi (29.8/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 39-69456[2]
GNIS feature ID 1086478[1]

St. Albans Township is one of the twenty-five townships of Licking County, Ohio, United States. The 2000 census found 2,060 people in the township, 1,975 of whom lived in the unincorporated portions of the township.[3]

Geography[edit]

Located in the western part of the county, it borders the following townships and city:

The village of Alexandria is located in central St. Albans Township.

Name and history[edit]

It is the only St. Albans Township statewide.[4]

Government[edit]

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[5] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.

References[edit]

External links[edit]