# Standard score

(Redirected from Standardizing)
"Standardize" redirects here. For industrial and technical standards, see Standardization.
For Fisher z-transformation in statistics, see Fisher transformation. For Z-values in ecology, see Z-value. For z-transformation to complex number domain, see Z-transform. For Z-factor in high-throughput screening, see Z-factor.
Compares the various grading methods in a normal distribution. Includes: Standard deviations, cumulative percentages, percentile equivalents, Z-scores, T-scores, standard nine, percent in stanine

In statistics, the standard score is the (signed) number of standard deviations an observation or datum is above the mean. Thus, a positive standard score indicates a datum above the mean, while a negative standard score indicates a datum below the mean. It is a dimensionless quantity obtained by subtracting the population mean from an individual raw score and then dividing the difference by the population standard deviation. This conversion process is called standardizing or normalizing (however, "normalizing" can refer to many types of ratios; see normalization (statistics) for more).

Standard scores are also called z-values, z-scores, normal scores, and standardized variables; the use of "Z" is because the normal distribution is also known as the "Z distribution". They are most frequently used to compare a sample to a standard normal deviate, though they can be defined without assumptions of normality.

The z-score is only defined if one knows the population parameters; if one only has a sample set, then the analogous computation with sample mean and sample standard deviation yields the Student's t-statistic.

The standard score is not the same as the z-factor used in the analysis of high-throughput screening data though the two are often conflated.

## Calculation from raw score

The standard score of a raw score x [1] is

$z = {x- \mu \over \sigma}$

where:

μ is the mean of the population;
σ is the standard deviation of the population.

The absolute value of z represents the distance between the raw score and the population mean in units of the standard deviation. z is negative when the raw score is below the mean, positive when above.

A key point is that calculating z requires the population mean and the population standard deviation, not the sample mean or sample deviation. It requires knowing the population parameters, not the statistics of a sample drawn from the population of interest. But knowing the true standard deviation of a population is often unrealistic except in cases such as standardized testing, where the entire population is measured. In cases where it is impossible to measure every member of a population, the standard deviation may be estimated using a random sample.

It measures the sigma distance of actual data from the average.

The Z value provides an assessment of how off-target a process is operating.

## Applications

The z-score is often used in the z-test in standardized testing – the analog of the Student's t-test for a population whose parameters are known, rather than estimated. As it is very unusual to know the entire population, the t-test is much more widely used.

Also, standard score can be used in the calculation of prediction intervals. A prediction interval [L,U], consisting of a lower endpoint designated L and an upper endpoint designated U, is an interval such that a future observation X will lie in the interval with high probability $\gamma$, i.e.

$P(L

For the standard score Z of X it gives:[2]

$P\left( \frac{L-\mu}{\sigma} < Z < \frac{U-\mu}{\sigma} \right) = \gamma.$

By determining the quantile z such that

$P\left( -z < Z < z \right) = \gamma$

it follows:

$L=\mu-z\sigma,\ U=\mu+z\sigma$

## Standardizing in mathematical statistics

Further information: Normalization (statistics)

In mathematical statistics, a random variable X is standardized by subtracting its expected value $\operatorname{E}[X]$ and dividing the difference by its standard deviation $\sigma(X) = \sqrt{\operatorname{Var}(X)}:$

$Z = {X - \operatorname{E}[X] \over \sigma(X)}$

If the random variable under consideration is the sample mean of a random sample $\ X_1,\dots, X_n$ of X:

$\bar{X}={1 \over n} \sum_{i=1}^n X_i$

then the standardized version is

$Z = \frac{\bar{X}-\operatorname{E}[X]}{\sigma(X)/\sqrt{n}}.$

See normalization (statistics) for other forms of normalization.