Strictly non-palindromic number
A strictly non-palindromic number is an integer n that is not palindromic in any numeral system with a base b in the range 2 ≤ b ≤ n − 2. For example, the number six is written as 110 in base 2, 20 in base 3 and 12 in base 4, none of which is a palindrome—so 6 is strictly non-palindromic.
Besides, the number 167 written in base b is:
|167 will be written as:||10100111||20012||2213||1132||435||326||247||205||167||142||11B||CB||BD||B2||A7||9E||95||8F||87||7K||7D||76||6N||...||15||14||13||12|
and none of which is a palindrome, so 167 is also a strictly non-palindromic number.
To test whether a number n is strictly non-palindromic, it must be verified that n is non-palindromic in all bases up to n − 2. The reasons for this upper limit are:
- any n ≥ 2 is written 11 in base n − 1, so n is palindromic in base n − 1;
- any n ≥ 2 is written 10 in base n, so any n is non-palindromic in base n;
- any n ≥ 1 is a single-digit number in any base b > n, so any n is palindromic in all such bases.
Thus it can be seen that the upper limit of n − 2 is necessary to obtain a mathematically 'interesting' definition.
For example, 167 will be written as:
|167 will be written as:||111111111111......111111111111 (167 1's)||11||10||a single-digit number|
For n < 4 the range of bases is empty, so these numbers are strictly non-palindromic in a trivial way.
All strictly non-palindromic numbers beyond 6 are prime. To see why composite n > 6 cannot be strictly non-palindromic, for each such n a base b must be shown to exist where n is palindromic.
- If n is even, then n is written 22 (a palindrome) in base b = n/2 − 1.
Otherwise n is odd. Write n = p · m, where p is the smallest prime factor of n. Then clearly p ≤ m.
- If p = m = 3, then n = 9 is written 1001 (a palindrome) in base b = 2.
- If p = m > 3, then n is written 121 (a palindrome) in base b = p − 1.
Otherwise p < m − 1. The case p = m − 1 cannot occur because both p and m are odd.
- Then n is written pp (the two-digit number with each digit equal to p, a palindrome) in base b = m − 1.
The reader can easily verify that in each case (1) the base b is in the range 2 ≤ b ≤ n − 2, and (2) the digits ai of each palindrome are in the range 0 ≤ ai < b, given that n > 6. These conditions may fail if n ≤ 6, which explains why the non-prime numbers 1, 4 and 6 are strictly non-palindromic nevertheless.
Therefore, all strictly non-palindromic n > 6 are prime.