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I am not an expert, but something wrong seems to me. "It is equivalent to the proper time experienced by a clock at rest in a coordinate frame co-moving with the barycenter of the Solar system: that is, a clock that performs exactly the same movements as the Solar system but is outside the system's gravity well "
I don't see the logic in the conjunction "that is": I don't see how the statement "outside gravity well" follows from "co-moving with the barycenter". By the way, do we really need the term "co-moving" rather something in plain English? By the way "co-moving" explained "same movements as Solar system". Which exactly movements are in mind? - Altenmann >t 17:22, 4 March 2010 (UTC)
Infinite distance because of the solar system gravity well effects the speed of time, co-moving, because motion effects the speed of time. The movements are the solar system's galactic orbit, Milky Way proper motion etc. Sagittarian Milky Way (talk) 21:56, 18 May 2012 (UTC)
The phrase "comoving with the barycentre of the solar system" refers to a frame which is moving the same way as the barycentre is, but with the solar system itself magicked away, and so not distorting spacetime locally, by its mass. The term "co-moving" is the right one to use here: it's reasonably intelligible to a non-technical reader, clearly indicating "moving along with"; but it will be recognised as the correct technical term, with the appropriate implications, by anyone who knows the term. That way, the page is useful to someone who is familiar with 'comoving', but also as parseable as it can be to the non-technical reader. NormanGray (talk) 08:30, 13 June 2012 (UTC)