Talk:De Sitter–Schwarzschild metric

Page contents not supported in other languages.
From Wikipedia, the free encyclopedia

Reason for being[edit]

This solution is well known, and has interesting properties. It is a limit where black hole singularities run away to infinity and disappear.Likebox (talk) 20:29, 19 May 2009 (UTC)[reply]

Schwartzschild/Schwartschild/Schwarzschild[edit]

Sure every Schwartzschild (and even once a Schwartschild) should rather be Schwarzschild? Seattle Jörg (talk) 10:01, 24 July 2009 (UTC)[reply]

I went through with moving the page and correcting the instances in the article.Seattle Jörg (talk) 11:06, 30 August 2009 (UTC)[reply]

N-dim metric, penrose diagram[edit]

It would be nice to see the N-dim metric written down, as it is mentioned. And perhaps an appropriately labelled penrose diagram to illustrate some of the discussion? I didn't really follow the bit about Susskind and Hawking. User:Linas (talk) 04:59, 3 November 2013 (UTC)[reply]

Inaccuracies?[edit]

The article says, "The metric of any spherically symmetric solution in Schwarzschild form is:" and shows a metric with g00 = -1/g11. However, I believe spherically symmetric metrics only take this form for certain equations of state. Generally speaking g00 does not equal the negative inverse of g11.

Also the Schwarzschild de Sitter solution is not a "superposition" as the article claims. The Schwarzschild de Sitter solution is an exact solution to Einstein's Field Equations for a constant background density. The Schwarzschild term enters as a constant of integration. 70.57.229.175 (talk) 20:45, 10 November 2018 (UTC) Kathleen A. Rosser[reply]