Talk:Dimension (vector space)

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Mathematics rating:
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 Field: Algebra

Why is the Hamil dimension well-defined? I would like to find a proof.

Have a tolerable existence. Eli <ecooper@mathstat.umass.edu>

Have a look at the following web-page: http://www.uwm.edu/~adbell/Teaching/631/1999/631notes7L/node1.html . I haven't read it, but it seems to cover what you want. It first does the finite-dimensional case, and then explains how to modify the proof to deal with the infinite-dimensional case. --Zundark 09:47, 8 Oct 2003 (UTC)

I'm CERTAIN that the general case needs the axiom of choice. A Geek Tragedy 16:07, 1 July 2007 (UTC)


i am new to this. The first example is a three by three matrix, therefore, I cannot tell if the dimension dim = 3 is the number of rows or number of columns. — Preceding unsigned comment added by 156.26.32.165 (talk) 00:16, 17 May 2013 (UTC)