Talk:Immediately-invoked function expression

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Note that code samples from Alman's page are licensed under the GPL and so may be used with attribution.

This code snippet is incorrect:

var v, getValue;
v = 1;
getValue = (function(v) {
  return v;
}(v));
v = 2;
 
getValue(); // 1

`getValue` is the number 1, not a function. 88.90.244.215 (talk) 19:40, 3 April 2013 (UTC) Later yo