# Talk:Nakagami distribution

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The legend of the first graph shows "omega = 1 = 2". 1 = 2 is rubbish. 131.215.45.223 (talk) 21:44, 28 April 2008 (UTC)

From M.Nakagamis 1960 paper, page 10, the MGF is as follows: $E\left[X^k\right] = \frac{\Gamma(\mu + k/2)}{\Gamma(\mu)\mu^{k/2}}\omega^{k/2}$— Preceding unsigned comment added by 80.3.31.37 (talk) 13:12, 16 September 2010

## formula for the median (table on the right)

The formula for the median in the table on the right "median = square root (ω)" cannot be correct. If so, all curves with the same ω in fig. 2 (Cumulative distribution function) should cross at the same point: cdf(median) = 0,5 I am not so familiar with the Nakagami distribution, therefore I don't know the correct formula. Hartmut Voigt --217.93.248.136 (talk) 12:14, 22 February 2011 (UTC)

## On-line reference

There is difficulty with the online reference to work by Laurenson. This depends on browsers being able to deal with the XBM format which, acoording to XBM is not supported by IE or Mozilla. Is there an alternative? Melcombe (talk) 16:32, 22 July 2011 (UTC)

## m<0.5

It seems that in some applications, 0<m<0.5 is possible as well. Maybe this should be mentioned? See eg.:

Dumane, V.A.; Shankar, P.M.; , "Use of frequency diversity and Nakagami statistics in ultrasonic tissue characterization," Ultrasonics, Ferroelectrics and Frequency Control, IEEE Transactions on , vol.48, no.4, pp.1139-1146, July 2001 doi: 10.1109/58.935733

VladimirSlavik (talk) 14:05, 15 November 2012 (UTC)