# Johnson–Nyquist noise

(Redirected from Thermal noise)
These three circuits are all equivalent: (A) A resistor at nonzero temperature, which has Johnson noise; (B) A noiseless resistor in series with a noise-creating voltage source (i.e. the Thévenin equivalent circuit); (C) A noiseless resistance in parallel with a noise-creating current source (i.e. the Norton equivalent circuit).

Johnson–Nyquist noise (thermal noise, Johnson noise, or Nyquist noise) is the electronic noise generated by the thermal agitation of the charge carriers (usually the electrons) inside an electrical conductor at equilibrium, which happens regardless of any applied voltage. The generic, statistical physical derivation of this noise is called the fluctuation-dissipation theorem, where generalized impedance or generalized susceptibility is used to characterize the medium.

Thermal noise in an ideal resistor is approximately white, meaning that the power spectral density is nearly constant throughout the frequency spectrum (however see the section below on extremely high frequencies). When limited to a finite bandwidth, thermal noise has a nearly Gaussian amplitude distribution.[1]

## History

This type of noise was first measured by John B. Johnson at Bell Labs in 1926.[2][3] He described his findings to Harry Nyquist, also at Bell Labs, who was able to explain the results.[4]

## Noise voltage and power

Thermal noise is distinct from shot noise, which consists of additional current fluctuations that occur when a voltage is applied and a macroscopic current starts to flow. For the general case, the above definition applies to charge carriers in any type of conducting medium (e.g. ions in an electrolyte), not just resistors. It can be modeled by a voltage source representing the noise of the non-ideal resistor in series with an ideal noise free resistor.

The one-sided power spectral density, or voltage variance (mean square) per hertz of bandwidth, is given by

$\overline {v_{n}^2} = 4 k_\text{B} T R$

where kB is Boltzmann's constant in joules per kelvin, T is the resistor's absolute temperature in kelvin, and R is the resistor value in ohms (Ω). Use this equation for quick calculation, at room temperature:

$\sqrt{\overline {v_{n}^2}} = 0.13 \sqrt{R} ~\mathrm{nV}/\sqrt{\mathrm{Hz}}.$

For example, a 1 kΩ resistor at a temperature of 300 K has

$\sqrt{\overline {v_{n}^2}} = \sqrt{4 \cdot 1.38 \cdot 10^{-23}~\mathrm{J}/\mathrm{K} \cdot 300~\mathrm{K} \cdot 1~\mathrm{k}\Omega} = 4.07 ~\mathrm{nV}/\sqrt{\mathrm{Hz}}.$

For a given bandwidth, the root mean square (RMS) of the voltage, $v_{n}$, is given by

$v_{n} = \sqrt{\overline {v_{n}^2}}\sqrt{\Delta f } = \sqrt{ 4 k_\text{B} T R \Delta f }$

where Δf is the bandwidth in hertz over which the noise is measured. For a 1 kΩ resistor at room temperature and a 10 kHz bandwidth, the RMS noise voltage is 400 nV.[5] A useful rule of thumb to remember is that 50 Ω at 1 Hz bandwidth correspond to 1 nV noise at room temperature.

A resistor in a short circuit dissipates a noise power of

$P = {v_{n}^2}/R = 4 k_\text{B} \,T \Delta f.$

The noise generated at the resistor can transfer to the remaining circuit; the maximum noise power transfer happens with impedance matching when the Thévenin equivalent resistance of the remaining circuit is equal to the noise generating resistance. In this case each one of the two participating resistors dissipates noise in both itself and in the other resistor. Since only half of the source voltage drops across any one of these resistors, the resulting noise power is given by

$P = k_\text{B} \,T \Delta f$

where P is the thermal noise power in watts. Notice that this is independent of the noise generating resistance.

## Noise current

The noise source can also be modeled by a current source in parallel with the resistor by taking the Norton equivalent that corresponds simply to divide by R. This gives the root mean square value of the current source as:

$i_n = \sqrt {{4 k_\text{B} T \Delta f } \over R}.$

Thermal noise is intrinsic to all resistors and is not a sign of poor design or manufacture, although resistors may also have excess noise.

## Noise power in decibels

Signal power is often measured in dBm (decibels relative to 1 milliwatt). From the equation above, noise power in a resistor at room temperature, in dBm, is then:

$P_\mathrm{dBm} = 10\ \log_{10}(k_\text{B} T \Delta f \times 1000)$

where the factor of 1000 is present because the power is given in milliwatts, rather than watts. This equation can be simplified by separating the constant parts from the bandwidth:

$P_\mathrm{dBm} = 10\ \log_{10}(k_\text{B} T \times 1000) + 10\ \log_{10}(\Delta f)$

which is more commonly seen approximated for room temperature (T = 300 K) as:

$P_\mathrm{dBm} = -174 + 10\ \log_{10}(\Delta f)$

where $\Delta f$ is given in Hz; e.g., for a noise bandwidth of 40 MHz, $\Delta f$ is 40,000,000.

Using this equation, noise power for different bandwidths is simple to calculate:

Bandwidth $(\Delta f )$ Thermal noise power Notes
1 Hz −174 dBm
10 Hz −164 dBm
100 Hz −154 dBm
1 kHz −144 dBm
10 kHz −134 dBm FM channel of 2-way radio
15 kHz −132.24 dBm One LTE subcarrier
100 kHz −124 dBm
180 kHz −121.45 dBm One LTE resource block
200 kHz −121 dBm GSM channel
1 MHz −114 dBm Bluetooth channel
2 MHz −111 dBm Commercial GPS channel
3.84 MHz −108 dBm UMTS channel
6 MHz −106 dBm Analog television channel
20 MHz −101 dBm WLAN 802.11 channel
40 MHz −98 dBm WLAN 802.11n 40 MHz channel
80 MHz −95 dBm WLAN 802.11ac 80 MHz channel
160 MHz −92 dBm WLAN 802.11ac 160 MHz channel
1 GHz −84 dBm UWB channel

## Thermal noise on capacitors

Thermal noise on capacitors is referred to as kTC noise. Thermal noise in an RC circuit has an unusually simple expression, as the value of the resistance (R) drops out of the equation. This is because higher R contributes to more filtering as well as to more noise. The noise bandwidth of the RC circuit is 1/(4RC),[6] which can substituted into the above formula to eliminate R. The mean-square and RMS noise voltage generated in such a filter are:[7]

$\overline {v_{n}^2} = k_\text{B} T / C$
$v_{n} = \sqrt{ k_\text{B} T / C }.$

Thermal noise accounts for 100% of kTC noise, whether it is attributed to the resistance or to the capacitance.

In the extreme case of the reset noise left on a capacitor by opening an ideal switch, the resistance is infinite, yet the formula still applies; however, now the RMS must be interpreted not as a time average, but as an average over many such reset events, since the voltage is constant when the bandwidth is zero. In this sense, the Johnson noise of an RC circuit can be seen to be inherent, an effect of the thermodynamic distribution of the number of electrons on the capacitor, even without the involvement of a resistor.

The noise is not caused by the capacitor itself, but by the thermodynamic equilibrium of the amount of charge on the capacitor. Once the capacitor is disconnected from a conducting circuit, the thermodynamic fluctuation is frozen at a random value with standard deviation as given above.

The reset noise of capacitive sensors is often a limiting noise source, for example in image sensors. As an alternative to the voltage noise, the reset noise on the capacitor can also be quantified as the electrical charge standard deviation, as

$Q_{n} = \sqrt{ k_\text{B} T C }.$

Since the charge variance is $k_\text{B} T C$, this noise is often called kTC noise.

Any system in thermal equilibrium has state variables with a mean energy of kT/2 per degree of freedom. Using the formula for energy on a capacitor (E = ½CV2), mean noise energy on a capacitor can be seen to also be ½C(kT/C), or also kT/2. Thermal noise on a capacitor can be derived from this relationship, without consideration of resistance.

The kTC noise is the dominant noise source at small capacitors.

Noise of capacitors at 300 K
Capacitance $\sqrt{ k_\text{B} T / C }$ Electrons
1 fF 2 mV 12.5 e
10 fF 640 µV 40 e
100 fF 200 µV 125 e
1 pF 64 µV 400 e
10 pF 20 µV 1250 e
100 pF 6.4 µV 4000 e
1 nF 2 µV 12500 e

## Noise at very high frequencies

Main article: Planck's law

The above equations are good approximations at frequencies below about 80 gigahertz (EHF). In the most general case, which includes up to optical frequencies, the power spectral density of the voltage across the resistor R, in V2/Hz is given by:[8]

$\Phi (f) = \frac{2 R h f}{e^{\frac{h f}{k_\text{B} T}} - 1}$

where f is the frequency, h Planck's constant, kB Boltzmann constant and T the temperature in kelvin. If the frequency is low enough, that means:

$f \ll \frac{k_\text{B} T}{h}$

(this assumption is valid until few terahertz at room temperature) then the exponential can be approximated by the constant and linear terms of its Taylor series. The relationship then becomes:

$\Phi (f) \approx 2 R k_\text{B} T.$

In general, both R and T depend on frequency. In order to know the total noise it is enough to integrate over all the bandwidth. Since the signal is real, it is possible to integrate over only the positive frequencies, then multiply by 2. Assuming that R and T are constants over all the bandwidth $\Delta f$, then the root mean square (RMS) value of the voltage across a resistor due to thermal noise is given by

$v_n = \sqrt { 4 k_\text{B} T R \Delta f },$

that is, the same formula as above.