United States Senate election in Iowa, 1980

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United States Senate election in Iowa, 1980
Iowa
1974 ←
November 3, 1980
→ 1986

  Sen Chuck Grassley official.jpg John Culver.jpg
Nominee Chuck Grassley John Culver
Party Republican Democratic
Popular vote 683,014 581,545
Percentage 53.49% 45.54%

Senator before election

John Culver
Democratic

Elected Senator

Chuck Grassley
Republican

The 1980 United States Senate election in Iowa was held on November 3, 1980. Incumbent Democratic United States Senator John Culver sought re-election to a second term in the Senate, but he was unsuccessful in his bid to do so, falling to Chuck Grassley, the United States Congressman from Iowa's 3rd congressional district, the Republican nominee.

Democratic primary[edit]

Candidates[edit]

Results[edit]

Democratic primary results[1]
Party Candidate Votes %
Democratic John Culver (inc.) 95,656 99.95%
Democratic Write-ins 52 0.05%
Totals 95,708 100.00%

Republican primary[edit]

Candidates[edit]

Results[edit]

Republican primary results[1]
Party Candidate Votes %
Republican Chuck Grassley 170,120 65.54%
Republican Tom Stoner 89,409 34.45%
Republican Write-ins 34 0.01%
Totals 259,563 100.00%

General election[edit]

Results[edit]

United States Senate election in Iowa, 1980[2]
Party Candidate Votes % ±%
Republican Chuck Grassley 683,014 53.49% +4.21%
Democratic John Culver (inc.) 581,545 45.54% -4.48%
Independent Garry De Young 5,858 0.46%
Libertarian Robert V. Hengerer 4,233 0.33%
Independent John Ingram Henderson 2,336 0.18%
Majority 101,469 7.95% +7.20%
Turnout 1,772,983
Republican gain from Democratic Swing

References[edit]