United States presidential election in Connecticut, 1828

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United States presidential election in Connecticut, 1828
Connecticut
1824 ←
October 31 – December 2, 1828
→ 1832

  JohnQAdams.png Andrew Jackson.jpg
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 8 4,448
Popular vote 13,829 22.95
Percentage 71.36% 22.95%

The 1828 United States presidential election in Connecticut took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Connecticut by a margin of 48.41%.

Results[edit]

United States presidential election in Connecticut, 1828[1]
Party Candidate Votes Percentage Electoral votes
National Republican John Quincy Adams 13,829 71.36% 8
Democratic Andrew Jackson 4,448 22.95% 0
N/A Other 1,101 5.68% 0
Totals 19,378 100.0% 8

References[edit]

  1. ^ "1828 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 28 February 2013.