United States presidential election in Idaho, 1992

Main article: United States presidential election, 1992

United States presidential election in Idaho, 1992

1988 ← November 3, 1992 → 1996

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 4 0 0 Popular vote 202,645 137,013 130,395 Percentage 42.03% 28.42% 27.05%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

Elections in Idaho
Federal government Presidential elections 1964 1992 1996 2000 2004 2008 2012 Presidential primaries Democratic Caucuses 2008 Republican Primaries 2008 2012 U.S. Senate elections 1980 1986 1992 1996 1998 2002 2004 2008 2010 2014 U.S. House elections 2006 2008 2010 2012
State government State legislature elections 2006
Ballot measures Gubernatorial elections Amendment 2 Proposition 2

The 1992 United States presidential election in Idaho took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Idaho was won by incumbent President George H.W. Bush (R-Texas) with 42.03% of the popular vote over Governor Bill Clinton (D-Arkansas) with 28.42%. Businessman Ross Perot (I-Texas) finished in a close third with 27.05% of the popular vote. Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.

Results

United States presidential election in Idaho, 1992
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H.W. Bush (incumbent)	202,645	42.03%	4
	Democratic	Bill Clinton	137,013	28.42%	0
	Independent	Ross Perot	130,395	27.05%	0
	Populist	James Bo Gritz	10,281	2.13%	0
	N/A	Other	1,780	0.37%	0
Totals			482,114	100.0%	4