United States presidential election in Kansas, 1996
|Elections in Kansas|
The 1996 United States presidential election in Kansas took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 6 representatives, or electors to the Electoral College, who voted for President and Vice President.
Kansas was won by Senator Bob Dole (R-KS) over President Bill Clinton (D), with Dole winning 54.29% to 36.08% by a margin of 18.21%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 8.62% of the popular vote, a sharp decline from 1992, when Perot captured 27% of the state's votes and held George H.W. Bush's victory margin to just over 5%.
|United States presidential election in Kansas, 1996|
|Party||Candidate||Running mate||Votes||Percentage||Electoral votes|
|Republican||Bob Dole||Jack Kemp||583,245||54.29%||6|
|Democratic||Bill Clinton (incumbent)||Al Gore||387,659||36.08%||0|
|Reform||Ross Perot||James Campbell ||92,639||8.62%||0|
|Libertarian||Harry Browne||Jo Jorgensen||4,557||0.42%||0|
|Independent||Howard Phillips||Herbert Titus||3,519||0.33%||0|
|Independent||Dr. John Hagelin||Dr. V. Tompkins||1,655||0.15%||0|
|Write-in||Ralph Nader||Winona LaDuke||914||0.09%||0|
|Write-in||Charles Collins||Rosemary Giumarra||112||0.01%||0|
- Dave Leip's Atlas of United States Presidential Election Results - 1996 Kansas Results
- Perot Names Stand-in Veep Candidate http://www-cgi.cnn.com/ALLPOLITICS/1996/news/9608/21/perot.veep/