United States presidential election in Maryland, 1988

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United States presidential election in Maryland, 1988
Maryland
1984 ←
November 8, 1988
→ 1992

  George H. W. Bush, President of the United States, official portrait.jpg Dukakis1988rally cropped.jpg
Nominee George H.W. Bush Mike Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 10 0
Popular vote 876,167 826,304
Percentage 51.11% 48.20%

MD1988.jpg

County Results
  Dukakis—70-80%
  Dukakis—60-70%
  Dukakis—50-60%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%

President before election

Ronald Reagan
Republican

Elected President

George H.W. Bush
Republican

The 1988 United States presidential election in Maryland took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland was won by Vice President George H.W. Bush (R-Texas), with 51.11% of the popular vote, over Massachusetts Governor Mike Dukakis (D-Massachusetts) with 48.20% of the popular vote.[1] Bush ultimately won the national vote, defeating Governor Dukakis.[2]

Results[edit]

United States presidential election in Maryland, 1988[1]
Party Candidate Votes Percentage Electoral votes
Republican George H.W. Bush 876,167 51.11% 10
Democratic Mike Dukakis 826,304 48.20% 0
Libertarian Ron Paul 6,748 0.39% 0
New Alliance Lenora Fulani 5,115 0.29% 0
N/A Write-ins 24 <0.01% 0
Totals 1,714,358 100.0% 10

References[edit]

  1. ^ a b "1988 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 8 June 2012. 
  2. ^ "1988 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.