United States presidential election in Nevada, 1904

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United States presidential election in Nevada, 1904
Nevada
1900 ←
November 8, 1904 → 1908

  Theodore Roosevelt (Nobel 1906).png AltonBParker.png
Nominee Theodore Roosevelt Alton B. Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 3 0
Popular vote 6,864 3,982
Percentage 56.66% 32.87%

President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

The 1904 United States presidential election in Nevada took place on November 8, 1904 throughout all 45 states, which was part of the 1904 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Nevada was won by the Republican ticket of incumbent President Theodore Roosevelt NY) and Senator Charles W. Fairbanks (IN) by margin of 23.79 percentage points,[1] roughly mirroring the results of the national popular vote. Following this election, Nevada would eventually become a bellwether that reflected the results of every Presidential election with the exceptions of 1908 and 1976.

Results[edit]

United States presidential election in Nevada, 1904.[1]
Party Candidate Running mate Votes Percentage Electoral votes
Republican Theodore Roosevelt Charles W. Fairbanks 6,864 56.66% 3
Democratic Alton B. Parker Henry G. Davis 3,982 32.87% 0
Socialist Eugene V. Debs Ben Hanford 925 7.64% 0
Populist Thomas E. Watson Thomas Tibbles 344 2.84% 0
Totals 12,115 100.00% 3
Voter turnout (Voting age)

References[edit]