United States presidential election in Nevada, 1992
|Elections in Nevada|
|None of These Candidates|
The 1992 United States presidential election in Nevada took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Nevada was won by Governor Bill Clinton (D-Arkansas) with 37.36% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 34.73%. Businessman Ross Perot (I-Texas) finished in third with 26.19% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.
Clinton's win, although narrow, would mark the beginning of Nevada's transition from a safe Republican state into a swing state; in all three presidential elections held in the 1980s, Republicans had dominated Nevada by double digit margins and swept every county in the state. Although Clinton carried only 2 of the state's 17 counties, his win in Clark County, where Las Vegas is located, and the most populous county in the state, would prove the key to this and future Democratic victories in Nevada.
|United States presidential election in Nevada, 1992|
|Republican||George H.W. Bush (incumbent)||175,828||34.73%||0|
|America First||James "Bo" Gritz||2,892||0.57%||0|
|N/A||"None of these candidates"||2,537||0.50%||0|
|American Independent||Howard Phillips||677||0.13%||0|
|New Alliance||Lenora Fulani||483||0.10%||0|
|Natural Law||Dr. John Hagelin||338||0.07%||0|
- "1992 Presidential General Election Results - Nevada". U.S. Election Atlas. Retrieved 8 June 2012.
- "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.